Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
Answer:Exact Form:
4
√
5
Step-by-step explanation:
Answer:
A. 0
B. -66
C. 4
D. 998
E. -12
Step-by-step explanation:
A. By definition, the sum of anything and its additive inverse is zero.
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B. If you have trouble with sums, your calculator can help.
-22 + (-44) = -22 -44 = -66
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C. -36/x = -9 can be solved by multiplying by x and dividing by -9:
-36 = -9x
-36/-9 = x = 4
Since the product of the divisor and quotient is the dividend, dividing the dividend by either gives the other. Here, your dividend is -36 and your quotient is -9. To find the divisor, you can divide -36 by -9, as we did.
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D. The absolute value function changes the sign of negative numbers to positive:
|-998| = 998
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E. If you have trouble with sums, your calculator can help.
(−2)−[(−3)−(−7)−(−6)]
= -2 -(-3 +7 +6) = -2 -10 = -12
Well, considering the amount of gravity placed on a kitten on the 4th of June, the answer would be 42
