Answer:
60^3 + 8a -5
Step-by-step explanation:
Like opposite of 5 is 5×-1 = -5,
Opposite of -60³ - 8a +5 is:
-(-60³ - 8a +5)
60³ + 8a - 5
For

to be continuous at

, you need to have the limit from either side as

to be the same.


If

and

, then the limit from the right would be

, so the answer to part (1) is no, the function would not be continuous under those conditions.
This basically answers part (2). For the function to be continuous, you need to satisfy the relation

.
Part (c) is done similarly to part (1). This time, you need to limits from either side as

to match. You have


So,

and

have to satisfy the relation

, or

.
Part (4) is done by solving the system of equations above for

and

. I'll leave that to you, as well as part (5) since that's just drawing your findings.
Answer:
2.542
Step-by-step explanation:
Given the data :
Customer Pre-training Survey, x1 __Post-training Survey, x2 __ difference, d = (x2-x1)
A 6 8 2
B 5 5 0
C 10 10 0
D 7 10 3
E 6 8 2
F 5 6 1
G 2 8 6
This is a paired test as each subject has two different data values :
Difference in score, d :
dbar = Σd / n
dbar = (2+0+0+3+2+1+6) /
dbar = 14 / 7
dbar = 2
Standard deviation of d ; Sd = √[Σ(d - dbar)²/n-1]
Using calculator ; Sd = 2.082
Test statistic = dbar ÷ (Sd/√n)
Test statistic = 2 ÷ (2.082 / 7)
Test statistic = 2 ÷ 0.7869220
The statistic = 2.5415
The equation is 1.2t=50.2 And the solution is 42
8.6 because 8 is bigger than 6