Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer:
(6.5,3)
please see the attached picture for full solution...
Hope it helps...
Good luck on your assignment.....
Answer:
I think that her taking the skateboard is 4 times as fast as her walking.
Step-by-step explanation:
I got this because she traveled twice as long and twice as fast on the skateboard, so if you multiply it together, there u have it.
In 12 games last season the school baseball team scored 5, 11, 2, 0, 4, 8, 9, 6, 7, 4, 1, and 2 runs. What is the average number
Mashcka [7]
Hello there!
First, we need to put our data set into proper numerical order (least to greatest).
Set: , 1,2,2,4,4,5,6,7,8,9,11
Now, to find the mean, we need to add them all up.
1 + 2 + 2 + 4 + 4 + 5 + 6 + 7 + 8 + 9 + 11 = 59
Then, divide it by how many numbers there are : 12
59 divided by 12 = 4.9166667
Round it to the nearest tenth.
4.9166667 = 4.9
This means the average number of runs scored per game is 4.9 runs.
Do my home work so ya we landing at loot lake