2 is the answer. 5474862/9= 68318
Hope it’s correct and it helps!!
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
3x+x+20 = 180
4x = 180-20
4x = 160
x = 40
×+20+3x+2x+38+C=360
40+20+3×40+2×40+38+C=360
40+20+120+80+38+C=360
298+C=360
C=360-298
C =62°
Yo sup??
this is of the form called slope and point... hence
y-11=-4(x+2)
therefore the correct answer is option A
Hope this helps
Answer:
6
Step-by-step explanation:
a^2 + 8^2 = 10^2
a^2 + 64 = 100
a^2 = 36
sq root of a = sq root of 36
a = 6
