Answer:
1.1 : C - x^2 + x - 2
1.2 : A - 4a^2 - 6b^2 + 12
Step-by-step explanation:
When we have the expression p(x) - q(x), we can substitute those functions in:
(x^2 + 2x - 5) - (x - 3)
We can distribute:
x^2 + 2x - 5 - x + 3
and then combine like terms(2x & -x, -5 & 3)
x^2 + x - 2
This is the same as C.
We can start by distributing:
a^2 - 2b^2 + 3 - 4b^2 + 5 + 3a^2 + 4
Now, we can combine all the a^2 terms(a^2 & 3a^2):
4a^2 - 2b^2 + 3 - 4b^2 + 5 + 4
Then, we can combine the b^2 terms(-2b^2 & -4b^2):
4a^2 - 6b^2 + 3 + 4 + 5
and lastly, all the constants:
4a^2 - 6b^2 + 12
This aligns with option A
Answer:
a = 5
Step-by-step explanation:
According to the factor theorem, if x + 2 is a factor, then by dividing the polynomial by the binomial, we are meant not to have a remainder
In this case, the remainder would be zero
So, if we set the binomial equals zero and substitute the x-value into the polynomial, we are supposed to have 0
So we have this as;
x + 2 = 0
x = -2
-2^3 -2(-2)^2 -2(a) + 6 = 0
-8-8-2a + 6 = 0
-16 + 2a + 6 = 0
2a -10 = 0
2a = 10
a = 10/2
a = 5
Both terms have a 2x^4 in common. When this GCF is factored out you get 2x^4(x^2 - 6).
Answer is C
The answers you have for each of them are right
Answer:
9:15
Step-by-step explanation:
