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Svetllana [295]
3 years ago
9

Sarah has grades of 98 and 98 on her first two tests. If she wants an average of at least 80 after her third test, what score mu

st she make on that test
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
3 0
Total for first two test = 98 + 98 = 196

Total needed for 3 test = 80 x 3 = 240

Score needed for 3rd test = 240 - 196 = 44

Answer: 44
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Ty very much! Please help? :))
wlad13 [49]

Answer:

<em>Exact Form: </em>

\frac{8}{3}

<em>Decimal Form: </em>

2.6

<em>Mixed Number Form: </em>

2\frac{2}{3}

Hope this helps :)

<em>-ilovejiminssi♡</em>

4 0
2 years ago
Given that the length and width of a square is 4mm, what would the area be?
patriot [66]

Answer:

16mm

Step-by-step explanation:

Area= length x width

4mm x 4mm

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6 0
3 years ago
Write the equation for a line that has an initial value of 3 and 3/4 as it’s rate of change
frutty [35]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

initial value of 3, namely when x = 0, y = 3, so we have the point (0 , 3) and it has a rate or slope of 3/4.

(\stackrel{x_1}{0}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{3}{4}}(x-\stackrel{x_1}{0})\implies y=\cfrac{3}{4}x+3

3 0
2 years ago
Find the value of x.
bekas [8.4K]
10 - 2x = 120
120 + 10 = 130

130 / 2 = 65

x = 65

2(65) - 10 = 120
7 0
2 years ago
Read 2 more answers
One month, Jon worked 3 hours less than Chaya, and Angelica worked 4 hours more than Chaya. Together they worked 196 hours. Find
OleMash [197]

джон работал на 1 час меньше

3 0
3 years ago
Read 2 more answers
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