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vaieri [72.5K]
3 years ago
15

Drawing it out would be best can you help me please

Mathematics
1 answer:
leva [86]3 years ago
6 0

Answer:

z_1+z_2 = (-2,5)

Step-by-step explanation:

To Find: z_1+z_2

Solution :

Referring the given graph

We can find the coordinates of   z_1 and  z_2

Coordinates of   z_1= (-7,1)

Coordinates of  z_2= (5,4)

Thus Coordinates of  z_1+z_2 = (-7+5,1+4) = (-2,5)

Thus z_1+z_2 = (-2,5)

So, the point z_1+z_2 = (-2,5) is shown on the attached graph file

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Solve for c: a=7b+8c+9d-10
polet [3.4K]
<span>a=7b+8c+9d-10
a = 8c + 16d - 10
solve for c then
8c = a - 16d + 10
  c = (</span>a - 16d + 10) / 8
or
  c = a/8 - 2d + 5/4
7 0
3 years ago
Suppose three marksmen shoot at a target. The ith marksman fires ni times, hitting the target each time with probability Pi, ind
astraxan [27]

Answer:

Distribution is NOT binomial.

Step-by-step explanation:

In order to be a binomial distribution, the probability of success for each individual trial must be the same. Since each marksman hits the target with probability Pi, the probability of success (hitting the target) is not necessarily equal for all trials. Therefore, the distribution is not binomial.

In this case, the distribution would only be binomial if Pi was the same for every "ith" marksman.

6 0
2 years ago
This exercise involves the formula for the area of a circular sector. The area of a circle is 700 m2. Find the area of a sector
mezya [45]

Answer:

334.4 m²

Step-by-step explanation:

The formula for the area of a sector is given as:

1/2 × r² × θ

Where θ = Central angle

Area of a Circle = 700 m²

The formula for the area of a circle = πr²

r = Radius of a circle

r² = Area / π

r = √Area / π

r = √700/π

r = 14.927053304 m

Approximately, r = 14.93 m

Therefore, the area of the sector

= 1/2 × r² × θ

= 1/2 × 14.93² × 3 rad

= 334.35735 m²

Approximately, Area of the sector = 334.4 m²

4 0
2 years ago
Please help me...........................
malfutka [58]

Answer:

B

Step-by-step explanation: because this negative

4 0
2 years ago
Write 2^8 * 8^2 * 4^-4 in the form 2^n
Eva8 [605]

The given expression 2^8 * 8^2 * 4^-4 can be written in the exponential form 2^n as 2^6.

<h3>What are exponential forms?</h3>

The exponential form is a more convenient way to write repetitive multiplication of the same integer by using the base and its exponents.

<u>For example:</u>

If we have a*a*a*a, it can be written in exponential form as:

=a^4

where

  • a is the base, and
  • 4 is the power.

The power in this format reflects the number of times we multiply the base by itself. The exponent is also known as the index or power. 

From the information given:

We can write 2^8 * 8^2 * 4^-4 in form of 2^n as follows:

\mathbf{= 2^8\times (2^3)^2 \times (2^2)^{-4} }

\mathbf{= 2^8\times (2^6) \times (2^{-8}) }

\mathbf{= 2^{8+6+(-8)}}

\mathbf{= 2^{6}}

Therefore, we can conclude that by using the exponential form, the given expression 2^8 * 8^2 * 4^-4 in the form 2^n is 2^6.

Learn more about exponential forms here:

brainly.com/question/8844911

#SPJ1

4 0
2 years ago
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