Answer:
A rectangle with a length of 6 and width of 2.
The corners added up make a rectangle so it is the same as a rectangle. You can just multiply 6 x 2 = 12 to find the area. If you have any more questions you are welcome to ask
Step-by-step explanation:
Answer:
(2,-1)
Step-by-step explanation:
Solved using math.
Answer:
2.
a)1
b)1
c)1
Step-by-step explanation:
There's some identity trigonometric equation, which are valid for all angles,and they doesn't depends on the measure of angle!
some of em are follows:. (x is the given angle)
- sin(x)^2+cos(x)^2=1
- cosec(x)^2=1+cot(x)^2
- sec(x)^2=1+tan(x)^2
You can remember these identity, its gonna help alot.
now back to question,. {x is representing angles)
for (a) sin(x)^2+cos(x)^2=1, this is true for all x, dat means that for all the angle given in question(for ,15°,30°,45°,60° and 120°),we will get 1
for(b) ,
cosec(x)^2=1+cot(x)^2
i.e, cosec(x)^2-cot(x)^2=1, again this is true for all x dat means that for all the angle given in question ,we will get 1
for (c),
sec(x)^2=1+tan(x)^2
i.e,sec(x)^2-tan(x)^2=1,again this is true for all x, dat means that for all the angle given in question ,we will get 1
✌️:)
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!