<span>Let's solve your equation step-by-step.<span><span><span>5x</span>+<span><span>12</span><span>(<span><span>4x</span>+8</span>)</span></span></span>=25</span>Step 1: Simplify both sides of the equation.<span><span><span>5x</span>+<span><span>12</span><span>(<span><span>4x</span>+8</span>)</span></span></span>=25</span></span><span>Simplify: (Show steps)</span><span><span><span><span>7x</span>+4</span>=25</span>Step 2: Subtract 4 from both sides.<span><span><span><span>7x</span>+4</span>−4</span>=<span>25−4</span></span><span><span>7x</span>=21</span>Step 3: Divide both sides by 7.<span><span><span>7x</span>7</span>=<span>217</span></span><span>x=3</span><u>Answer:</u><span>x=<span>3</span></span></span>
Answer:
-6
Step-by-step explanation:
Are you sure that z + 2+ z is correct? x and y do not appear here.
z + 2+ z simplifies to 2z + 2, and so, if z = -4, z + 2+ z has the value
2(-4) + 2, or -6.
Answer:
y=5x+25
y=5(12)+25
y=85
Step-by-step explanation:
The answer is (-2,3)
hope you have a great day ;)
<u>ANSWER:
</u>
Zach has 28 dimes and 7 quarters.
<u>SOLUTION:
</u>
Given, Zach has 4 times as many dimes as quarters
And they have a combined value of 455 cents,
We need to find how many of each coins does he have?
Let, the number of dimes be x and number of quarters be y.
Then, x = 4y → (1)
Total combined value = 455 cents
x(value of one dime) + y(value of one quarter) = 455 cents
x(10 cents) + x(25 cents) = 455 cents
10x + 25y = 455 → (2)
Now, substitute (1) in (2)
10(4y) + 25y = 455
40x + 25y = 455
65y = 455
y = 7
substitute y value in (1)
x = 4(7) = 28
Hence, zach has 28 dimes and 7 quarters.
