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4 years ago

Y=8/3x-5 my teacher want me to find the slope and y-intercept for each equation

1 answer:

7 0

Each of these equations follows the standard form: y = mx + b

The variable "m" is the slope, and the variable "b" is the y-intercept.

Therefore, with the equation y = 8/3x - 5, the slope ("m") would equal 8/3 and the y-intercept ("b") would equal -5

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Someone help me please

Masteriza [31]

Answer:

$(5,1)$

Step-by-step explanation:

Hi there!

Midpoint = $\displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$ where the two endpoints are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given information:

Midpoint = (5,3), Endpoint = (5,5)

$(5,3)=\displaystyle (\frac{5+x_2}{2},\frac{5+y_2}{2} )$ where $(x_2,y_2)$ is the other endpoint

Solve for $x_2$ :

$\displaystyle \frac{5+x_2}{2} =5\\\\5+x_2 =10\\x_2 =5$

Solve for $y_2$ :

$\displaystyle\frac{5+y_2}{2}=3 \\\\{5+y_2}=6\\y_2=1$

Therefore, the other endpoint $(x_2,y_2)$ is $(5,1)$ .

I hope this helps!

4 0

3 years ago

Read 2 more answers

Solve for r 2r = 7/10

deff fn [24]

Answer:

7/20

Step-by-step explanation:

given,

2r = 7/10

r= 7/10*1/2

r= 7/20

6 0

3 years ago

What is the slope of the line in the graph? 4th possible answer is 4/3 ---- بنام

Delvig [45]

Answer: Second option.

Step-by-step explanation:

The slope of a line can be calculated with this formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Then, you need to choose two points of the line shown in the graph and substitute them into the formula for calculate the slope:

Let's pick the points (-4,4) and (4,-2).

Substituting:

$m=\frac{-2-4}{4-(-4)}$

Simplifiying, you get that the slope of the line in the graph is:

$m=\frac{-2-4}{4-(-4)}\\\\m=\frac{-6}{4+4}\\\\m=\frac{-6}{8}\\\\m=-\frac{3}{4}$

6 0

4 years ago

What does 9 ×9÷6-3 equal

Mkey [24]

Answer:

It equals 10.5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than

zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 3, n = 8

$$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)$

$$=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)$

$$=\left(\frac{81}{11} , \frac{-43}{11}\right)$

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 7, n = 1

$$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)$

$$=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)$

$$=\left(\frac{136}{8} , \frac{-12}{8}\right)$

C(x, y) = (17, –1.5)

8 0

3 years ago