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TEA [102]
3 years ago
15

Carson Company purchased a depreciable asset for $560,000. The estimated salvage value is $28,000, and the estimated useful life

is 10,000 hours. Carson used the asset for 1,500 hours in the current year. The activity method will be used for depreciation. What is the depreciation expense on this asset in the current year?
Business
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

$79,800

Explanation:

Depreciation expense using the activity method = (actual hours of use in a given period / total estimated hours of use ) × ( Cost of asset - Salvage value)

(1500/10,000) × ($560,000 - $28,000) = $79,800

I hope my answer helps you.

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An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0
4 years ago
A perfect hedge (full coverage) on translation exposure can usually be achieved when which of the following occurs? a. Using a f
attashe74 [19]

Answer:

e). None of the above, because a perfect hedge does not exist

A perfect hedge is nearly impossible

Explanation:

A perfect hedge is a position undertaken by an investor that would eliminate the risk of an existing position, or a position that eliminates all market risk from a portfolio. In order to be a perfect hedge, a position would need to have a 100% inverse correlation to the initial position.

At the time of taking an opposite position in Derivatives Market, Perfect Hedge would mean covering the risk involved in the Cash Market Position completely, i.e. 100%. 2. Imperfect Hedge: When the position in the cash market is not completely hedged or not hedged to 100%, then such a hedge is called Imperfect Hedge.

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3 years ago
Preston has to make four phone calls to clients today. The call to Mr. Miller will take about an hour to complete, the call to M
MrRissso [65]

Answer:

Preston has to make four phone calls to clients today. The call to Mr. Miller will take about an hour to complete, the call to Ms. Winnecuit will take about five minutes to complete, the call to Mr. Drudge will take about thirty minutes and the call to Mrs. Freich will take about fifteen minutes to complete. If all the calls are equally important, who should Preston call first?

From the analogy above, in order to maximize the time frame. The call to lesser clients should be prioritized before others, this means that Preston should place a call to Ms Winnecuit which will last for five minutes follow by Mrs Freich which will last for fifteen minutes follow by Mr Drudge which will last for thirty minutes and lastly to Mr Miller which will last for about an hour.

Prioritization comes in play to time frame of each call, the lesser minutes calls will not take too much time to be completed while the call with highest time frame comes last as a result of the time involved.

Explanation:

6 0
3 years ago
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What academic information do you have about sub-overseer?​
Olenka [21]

Explanation:

Pre-Diploma in Civil Engineering (Civil Sub-Overseer) program is designed to prepare competent general civil sub-overseers equipped with knowledge, skills and attitude especially, in the area construction Engineering & Technology of building construction, water supply, irrigation and road and trail bridges sectors.

They can provide services in the growing infrastructure development industries (civil construction companies and consulting firms) government institutions (centre and local level), local as well as international non-governmental organizations or can start their own business in the country as well as abroad.

4 0
3 years ago
Outline the process the raw ingredients for a single flavor of ice cream might undergo to get to a local grocery’s freezer case.
den301095 [7]

Answer: fermenting , shredding , pasteurizing

5 0
3 years ago
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