Your question has been heard loud and clear.
Lhs = 2cos[5A+3A/2]cos[5A-3A/2]+2cos[15A+7A/2]cos[15A-7A/2]
=2cos4AcosA+2cos11Acos4A
=2cos4A[cosA+cos11A]
=2cos4A[2cos[11A+A/2]Cos[11A-A/2]
=2cos4A2cos5Acos6A
=4cos4Acos5Acos6A=Rhs
Thank you
9514 1404 393
Answer:
m∠RPQ = 20°
Step-by-step explanation:
Exterior angle QRS is equal to the sum of interior angles RPQ and PQR.
7x +8 = (x +12) +(3x +20)
3x = 24 . . . . . . . . . . . . . . . . . . subtract 4x+8
x = 8
m∠RPQ = (x+12)° = (8+12)°
m∠RPQ = 20°
25, 7*4 = 28 32-28=4 and 42/6=7*3 = 21 + 4 = 25
You have a number -204
you need three numbers that come each after another
so (X-1)+X+(X+1)=-204
3X=-204
X=-68 (middle number)
so X-1=-69 (lower number)
X+1=-67 (higher number)
Dependent. This system is consistent, because the first equation can be rearranged to y+3x=5, which is exactly the same as the second equation, so they don't contradict each other. However, their are infinite number of solutions to the equation y+3x=5, like x=1, y=2; or x=2, y=-1;... so the system is dependent.