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lyudmila [28]
3 years ago
10

Consider the baggage check-in process of a small airline. Check-in data indicates that from 9am to 10am, 220 passengers checked

in. Moreover, based on counting the number of passengers waiting in line, airport management found that the average number of passengers waiting for check-in was 32. Instructions: Round your answer to 1 decimal place. How long did the average passenger have to wait in line?
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0

Answer:

3.6 minutes.

Step-by-step explanation:

According to the data given in the question, between 9 and 10 AM, 220 passengers have checked in which means that the check-in rate is 3.6 passengers per minute. If the average number of passengers waiting for check-in is 32 and if we assume that the check-in rate is constant throughout the day, then the average passenger had to wait in line for 3.6 minutes.

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Aiko jump roped for 20 minutes before stopping at 8:05. Just count 20 minutes back in order to see when she started.

8:05 - 20 minutes = 7:45
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Why do some metals react with only steam?​
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Answer:

Metals which react with steam form the solid metal oxide and hydrogen gas.

In general, the more reactive the metal, the more rapid the reaction. Aluminium is unusual, because it is a reactive metal that does not react with water. Its surface forms a protective layer of aluminium oxide that keeps water away from the metal below.

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Tonya has 39 packages.Each package weighs 6 pounds.<br> a.2,400lb<br> b.240lb<br> c.200lb<br> d20lb
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Each package weighs 6 pounds. Choose the best estimate of the total weight of the packages.2,400 pounds 240 pounds 200 pounds 20 pounds.

3 0
2 years ago
Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles. She can ride 9 mph faster than she can walk. How f
Marrrta [24]

Answer:

\frac{48}{r+9}=\frac{12}{r}

Step-by-step explanation:

Let r represent Linda's walking rate.                      

We have been given that Linda can ride 9 mph faster than she can walk, so Linda's bike riding rate would be t+9 miles per hour.

\text{Time}=\frac{\text{Distance}}{\text{Rate}}

We have been given that Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles.

\text{Time while riding}=\frac{48}{r+9}

\text{Time taken while walking}=\frac{12}{r}

Since both times are equal, so we will get:

\frac{48}{r+9}=\frac{12}{r}

Therefore, the equation \frac{48}{r+9}=\frac{12}{r} can be used to solve the rates for given problem.

Cross multiply:

48r=12r+108

48r-12r=12r-12r+108

36r=108

\frac{36r}{36}=\frac{108}{36}

r=3

Therefore, Linda's walking at a rate of 3 miles per hour.

Linda's bike riding rate would be t+9\Rightarrow 3+9=12 miles per hour.

Therefore, Linda's riding the bike at a rate of 12 miles per hour.

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3 years ago
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grigory [225]

Answer:

(x+3)(x+2)

Step-by-step explanation:

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