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lyudmila [28]
4 years ago
10

Consider the baggage check-in process of a small airline. Check-in data indicates that from 9am to 10am, 220 passengers checked

in. Moreover, based on counting the number of passengers waiting in line, airport management found that the average number of passengers waiting for check-in was 32. Instructions: Round your answer to 1 decimal place. How long did the average passenger have to wait in line?
Mathematics
1 answer:
Lady bird [3.3K]4 years ago
4 0

Answer:

3.6 minutes.

Step-by-step explanation:

According to the data given in the question, between 9 and 10 AM, 220 passengers have checked in which means that the check-in rate is 3.6 passengers per minute. If the average number of passengers waiting for check-in is 32 and if we assume that the check-in rate is constant throughout the day, then the average passenger had to wait in line for 3.6 minutes.

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ikadub [295]

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Step-by-step explanation:

5 0
4 years ago
I need to understand question 14 and 15 and the last one cut off for tens in one
sp2606 [1]

                                                 Question # 14

Given the numbers

10     11     12     13     14     15     16     17     18     19     20

Let 'x' be the number

The condition breakdown:

I am less than 20.

  • So the number 'x' must be less than 20 i.e. x < 20

I am more than 13.

  • So the number 'x' must be greater than 13 i.e. x > 13

I am less than 17.

  • So the number 'x' must be less than 17 i.e. x < 17

Finally:

I am 4 more than 12

i.e. 12+4 = 16

Thus, the number is x = 16

                                               Question # 15

Part a)

Given the numbers

10     11     12     13     14     15     16     17     18     19     20

Let 'x' be the number

The condition breakdown:

I am more than 10.

  • x > 10

I am less than 20.

  • x < 20

I am more than 12.

  • x > 12

I am less than 15.

  • x < 15

As the numbers left after all the conditions are fulfilled are 13 and 14.

  • But the last condition is, of the numbers that left, the number is greater than all the remaining numbers.

So, from the remaining number 13 and 14;

14 > 13

Thus, the number x = 14

Part b)

Drawing the number 14 in the place value:

          Chart

Tens                Ones

1                         4

6 0
3 years ago
An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

7 0
3 years ago
Find the focus for y=x^2+4x-7
padilas [110]

ANSWER

(2,-10.75)

EXPLANATION

The given function is

y =  {x}^{2}  - 4x - 7

We rewrite this function to obtain,

(y + 11) =  {( x- 2)}^{2}

We now compare this function to

(y  -  k) = 4p {( x- h)}^{2}

We have

4p = 1

This implies that,

p =  \frac{1}{4}

The vertex is (2,-11).

The focus is

(2,-11+ \frac{1}{4} )

(2,- \frac{43}{4} )

(2,-10.75)

7 0
3 years ago
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