The sum of three consecutive integers is three more than twice the middle integer. Create an equation and solve to find the inte
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Solution
f(x) = -20 +14x + 12 and g(x) = 5x - 6.
(f/g)(x) =
(f/g)(x) =
<u>Step 1: </u>Now we have to factorize the numerator.
f(x) = -20x^2 + 14x + 12
Factor out -2, we get
= -2 (10x^2 - 7x - 6)
Now we can factorize 10x^2 - 7x - 6
f(x) = -2(2x + 1) (5x - 6)
<u>Step 2: </u>Plug in the factors
(f/g)(x) =
<u>Step 3:</u> Cancel out the common factor (5x - 6) from the numerator and the denominator, we get
(f/g)(x) = -2(2x +1) = -4x -2
Since -4x -2 is linear expression, the domain is all the real numbers.
Therefore, the answer is –4x – 2; all real numbers
Thank you :)
<h2>A)</h2>