9514 1404 393
Answer:
B. (x +4)² +(y +5)² = 64
Step-by-step explanation:
The equation for a circle with center (h, k) and radius r is ...
(x -h)² +(y -k)² = r²
Filling in your given values, you have ...
(x -(-4))² +(y -(-5))² = 8²
Simplifying, you get ...
(x +4)² +(y +5)² = 64 . . . . . . . matches choice B
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<em>Additional comment</em>
As you learn more different "standard form" equations, it may be helpful to keep a list, along with reminders of what the variables stand for and how the equation is used.
Answer:
1995.26
Step-by-step explanation:
It usually works to follow instructions:
3.3 = log(x) . . . . . substitute known values into the equation
10^3.3 = x . . . . . take antilogs
1995.26 = x . . . . simplify, round to hundredths
Notation. x y means x is less than or equal to y. x y means x is greater than or equal to y. x < y means x is less than y. x > y means x is greater than y. The last two inequalities are called strict inequalities. Our focus will be on the nonstrict inequalities. Algebra of Inequalities Suppose x + 3 < 8. Addition works like for equations: x + 6 < 11 (added 3 to each side). Subtraction works like for equations: x + 2 < 7 (subtracted 4 from each side). Multiplication and division by positive numbers work like for equations: 2x + 12 < 22 =) x + 6 < 11 (each side is divided by 2 or multiplied by 1 2 ). 59 60 4. LINEAR PROGRAMMING Multiplication and division by negative numbers changes the direction of the inequality sign: 2x + 12 < 22 =) x 6 > 11 (each side is divided by -2 or multiplied by 1 2 ). Example. For 3x 4y and 24 there are 3 possibilities: 3x 4y = 24 3x 4y < 24 3x 4y > 24 4y = 3x + 24 4y < 3x + 24 4y > 3x + 24 y = 3 4x 6 y > 3 4x 6 y < 3 4x 6 The three solution sets above are disjoint (do not intersect or overlap), and their graphs fill up the plane. We are familiar with the graph of the linear equation. The graph of one inequality is all the points on one side of the line, the graph of the other all the points on the other side of the line. To determine which side for an inequality, choose a test point not on the line (such as (0, 0) if the line does not pass through the origin). Substitute this point into the linear inequality. For a true statement, the solution region is the side of the line that the test point is on; for a false statement, it is the other side.
