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Zarrin [17]
3 years ago
7

30 Points! The average distance from the sun to the planet Mercury is about 58,000,000 km. What is the distance from the sun to

Mercury written in scientific notation? Show your work.
Mathematics
1 answer:
stellarik [79]3 years ago
8 0

 58,000,000 km.

5.8 × 10⁷ Km

0.0025 cm

2.5 × 10⁻³ cm

5.8 × 10⁷ Km > 2.5 × 10⁻⁸


You might be interested in
¿Cuál es el área de un rectángulo, sabiendo que su perímetro mide 24 cm y que su base es el triple de su altura?
Brrunno [24]

Answer:

El área del rectángulo es:

27 cm²

Step-by-step explanation:

Consideración:

La formula del perímetro de un rectángulo es:

p = 2(altura + base)

Planteamiento:

24 = 2(a+b)

b = 3a

a = longitud de la altura del rectángulo

b = longitud de la base del rectángulo

Desarrollo:

sustituyendo el valor de la segunda ecuación del planteamiento en la primer ecuación del planteamiento:

24 = 2(a + 3a)

24/2 = 4a

12 = 4a

a = 12/4

a = 3 cm

de la segunda ecuación del planteamiento:

b = 3a

b = 3*3

b = 9 cm

Comprobación:

de la primer ecuación del planteamiento:

24 = 2(3+9)

24 = 2*12

Respuesta:

la formula del área de un rectángulo es:

A = base * altura

A = 9cn * 3cm

A = 27cm²

5 0
3 years ago
Which of the following statements is true
konstantin123 [22]
Hey!

The answer is option c).

√9 is a rational number as √9 = 3..

while √10 is an irrational number..

Hope it helps^^

5 0
3 years ago
Help! Can anyone Simplify this for me
Tcecarenko [31]
64x^{6} y^{12}
5 0
3 years ago
The Snyder family uses up a 1 2 -gallon jug of milk every 3 days. At what rate do they drink milk?
Cerrena [4.2K]

Answer: 4 gallons per day

Step-by-step explanation:

From the question, we are informed that the Snyder family uses up a 12 -gallon jug of milk every 3 days.

The rate at which they drink milk will be gotten by dividing the gallons of milk they drink by the number of days. This will be:

= 12/3

= 4 gallons per day

Therefore, the rate they use in taking milk is 4 gallons per day.

5 0
3 years ago
16. Which of the following are equivalent to(x) 16xA) g(r) 8.21B) g(c) 4096.16-3g (x) -4.4xD) g(x) 0.0625-16'+1E) g(x) 32.16E) g
swat32
F(x) = 16ˣ

A. g(x) = 8(2ˣ)
    g(x) = (2³)(2ˣ)
    g(x) = 2ˣ⁺³
The answer is not A.

B. g(x) = 4096(16ˣ⁻³)
    g(x) = (16³)(16ˣ⁻³)
    g(x) = 16ˣ
The answer is B.

C. g(x) = 4(4ˣ)
     g(x) = 4ˣ⁺¹
The answer is not C.

D. g(x) = 0.0625(16ˣ⁺¹)
     g(x) = (16⁻¹)(16ˣ⁺¹)
     g(x) = 16ˣ
The answer is D.

E. g(x) = 32(16ˣ⁻²)
    g(x) = (2⁵)(2⁴ˣ⁻⁸)
    g(x) = 2(⁴ˣ⁻³)
The answer is not E.

F. g(x) = 2(8ˣ)
    g(x) = 2(2³ˣ)
    g(x) = 2³ˣ⁺¹
The answer is not F.

The answer is B and D.
6 0
3 years ago
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