All categories

3 years ago

Please help me on my GEOMETRY question

Mathematics

2 answers:

GuDViN [60]3 years ago

8 0

∠ABX is an inscribed angle.
The measure of an inscribed angle is half the measure of the intercepted arc ⇒
arc AX = 2*∠ABX = 2 * 64 = 128°

The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the <span>intercepted arcs </span>⇒
∠ACB = (arc AB - arc AX)/2 = (152 - 128)/2 = 24/2 = 12°

dalvyx [7]3 years ago

5 0

I think 32.... don't count me on it tho

You might be interested in

Which number is an irrational number

mixer [17]

The square root of 11 since it can’t be solved repeating the same every time like the others! Hope this helps ☺️

7 0

3 years ago

Read 2 more answers

The manufacturer of an airport baggage scanning machine claims it can handle an average of 530 bags per hour. (a-1) At α = .05 i

fenix001 [56]

Answer:

Null hypothesis: $\mu \geq 250$

Alternative hypothesis: $\mu < 250$

$p_v =P(t_{15}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=510$ represent the mean for the sample

$s=50$ represent the standard deviation for the sample

$n=16$ sample size

$\mu_o =530$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the claim thet the handle on average is 530 bags per hour:

Null hypothesis: $\mu \geq 530$

Alternative hypothesis: $\mu < 530$

We don't know the population deviation and the sample size is lees than 30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{510-530}{\frac{50}{\sqrt{16}}}=-1.60$

4) Calculate the critical value

We need to begin calculating the degrees of freedom

$df=n-1=16-1=15$

The critical value for this case would be :

$P(t_{15}$

The value of a that satisfy this on the normal standard distribution is a=-1.75 and would be the critical value on this case zc=-1.75

5) Calculate the P-value

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}$

6) Conclusion

8 0

3 years ago

HELP MEE :)) PLEASEEE <3

Mandarinka [93]

<h3>Volume of the cylinder:</h3>

$v = \pi {r}^{2} h$

$v = 3.14 \times {2}^{2} \times 3$

$v = 37.68 \: {cm}^{3}$

<h3>Volume of the rectangular prism:</h3>

$v = lwh$

$v = 6 \times 5 \times 7$

$v = 210 \: {cm}^{3}$

<h3>Total volume:</h3>

$v = 37.68 + 210$

$v = 247.68 \: {cm}^{3}$

4 0

2 years ago

Read 2 more answers

If a basketball player made 72 out of 85 free throws attempts how many could she make in 200 attempts

DedPeter [7]

Answer:

169

Step-by-step explanation:

Use a proportion:

72/85=x/200

Solve for x

(72)(200)=85x

x=(72)(200)/85

x=169.41≈ 169

She can make 169 of 200 free throws.

6 0

2 years ago

There are 130 people in a sport centre.

Mashcka [7]

Answer:

Step-by-step explanation:

Using set notation to answer the question. let:

n(U) be the total people in a sport centre =130

n(G) be number of people that use the gym. = 76

n(P) be number of people that use the swimming pool. = 60

n(T) be number of people that use the track = 32

n(G∩P) be number of people that uses the gym and the pool = 23

n(P∩T) be number of people that uses the pool and the track = 8

n(G∩T) be number of people that uses the gym and the track = 320

n(G∩P∩T) be number of people that uses all three facilities = 6

Using the relationship below;

n(U)= n(GUPUT)+n(GUPUT)'

where n(GUPUT)' is the number of people that doesn't use any facility.

Before we can get that, we need to know n(GUPUT) using the formula;

n(GUPUT) = n(G) + n(P)+n(T)-n(G∩P)-n(P∩T)-n(G∩T)+n(G∩P∩T)

n(GUPUT) = 76+60+32-23-8-20+6

n(GUPUT) = 123

n(GUPUT)' = n(U)- n(GUPUT)

n(GUPUT)' = 130 - 123

n(GUPUT)' = 7

This means that 7 person doesn't use any facility.

Probability that a person selected at random doesn't use any facility = n(GUPUT)' /n(U) = 7/130

3 0

3 years ago