All that is needed is a single counter-example.
One counter-example is to multiply the monomial x^3 with the binomial x^7-10x^4
We then get...
x^3*(x^7-10x^4) = x^3*x^7 + x^3*(-10x^4)
x^3*(x^7-10x^4) = x^10 - x^7
The result we get is a binomial as there are still only two terms here. We would need three terms to have a trinomial.
Answer:
b because first u need to remove the parentheses then u disturbe
Answer:
x^2 + 3x - 18
Step-by-step explanation:
In order to solve this problem, I recommend using the FOIL method.
F = Front
O = Outer
I = Inner
L = Last
Start by multiplying the fronts which is x with x, which will give you x^2 (X to the second power).
Then, multiply x and -3, which gives you -3x. (Outer)
Third, multiply 6 and x, which gives you 6x. (Inner)
Finally, multiply 6 and -3, which gives you -18. (Last)
Now, there are like terms in the products that we just did which is 6x and -3x combine them together and you will get 3x.
So your results should be
x^2 + 3x - 18
Hope this helps!
