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Mamont248 [21]
2 years ago
6

The product of the page numbers on two facing pages of a book is 272272. find the page numbers.

Mathematics
1 answer:
labwork [276]2 years ago
4 0
Let n be the first page, and n+1 be the second. Then:
n(n+1)=272
n²+n-272=0
(n+17)(n-16)=0
n=16 or -17
If the first page is page 16, then the next is page 17
☺☺☺☺
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If<br> f(x) = x2 + 2x - 4<br> and<br> g(x) = 3x + 1<br> Find<br> f(g(x)) = [? ]x² +[? ]x+ [?]
zubka84 [21]
Your anwser is quit school ):73
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2 years ago
The following table shows the​ weights, in hundreds of​ pounds, for six selected cars. Also shown is the corresponding fuel​ eff
Reika [66]

Answer:

Step-by-step explanation:

Given is a table showing  the​ weights, in hundreds of​ pounds, for six selected cars. Also shown is the corresponding fuel​ efficiency, in miles per gallon​ (mpg), for the car in city driving.

Weight Fuel eff. x^2 xy y^2

X Y    

28 20 784 560 400

3 22 9 66 484

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30 23 900 690 529

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Mean 26.16666667 21.16666667 797.1666667 549 449.8333333

     

Variance   112.4722222  1.805555556

Covariance -553.8611111    

     

     

r -0.341120235    

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8 0
3 years ago
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
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