Answer:
I have no clue
Step-by-step explanation:
Answer: 1,098.1
Step-by-step explanation: Hope this helps, Merry Christmas, and have a nice day!
Answer:
11a. (1, 1)
11b. (2, 2)
Step-by-step explanation:
A function cannot have an x-value that produces multiple different y-values. A function can have a y-value that produces multiple different x-values.
For this question, you could put in a number of different points and still get the right answer. If you work through this problem yourself again and pick different points from mine, it doesn't mean that it is wrong. As long as it follows the rules stated above, you will get the correct answer.
11a. (1, 1)
This is an x-value that was not stated in the data set. This means that, as far as we know, there is only one y-value for the x-value of 1.
11b. (2, 2)
This is an x-value that was stated in the data set. This means that for the x-value of 2, there are two y-values: 2 and 8.
Quadratic
y = ax^2 + bx + d
c (x) = ax^2 + bx + d
c (3) = a (3^2) + b (3) + d
c (3) = 9a + 3b + d = 15.50
c (7) = a (7^2 + b (7) + d
c (7) = 49a + 7b + d = 23.50
c (12) = a (12^2) + b (12) + d
c (12) = 144a + 12b + d = 56
solve using simultaneous equations... to get a b and d
use that to solve for x = 5
hope this helps?
