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Oduvanchick [21]
3 years ago
10

What is the LCM of two numbers if one is the multiple of the other? Give example.

Mathematics
1 answer:
djyliett [7]3 years ago
6 0
Its usually each other like 5 and 10
The other one I don't know do you think you can try helping me with my homework?
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Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]
Zina [86]

Answer: Absolute minimum: f(-1) = -2\sqrt{6}

              Absolute maximum: f(\sqrt{12.5}) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = t\sqrt{25-t^{2}}

f'(t) = 1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)

f'(t) = \sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }

f'(t) = \frac{25-2t^{2}}{\sqrt{25-t^{2}} } = 0

For this function to be zero, only denominator must be zero:

25-2t^{2} = 0

t = ±\sqrt{2.5}

\sqrt{25-t^{2}} ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = -\sqrt{2.5} and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = t\sqrt{25-t^{2}}

f(-1) = -1\sqrt{25-(-1)^{2}}

f(-1) = -\sqrt{24}

f(-1) = -2\sqrt{6}

f(\sqrt{12.5}) = \sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}

f(\sqrt{12.5}) = 12.5

f(5) = 5\sqrt{25-5^{2}}

f(5) = 0

Therefore, absolute maximum is f(\sqrt{12.5}) = 12.5 and absolute minimum is

f(-1) = -2\sqrt{6}.

8 0
3 years ago
Identify the diameter of the circle. Then find the circumference. Round to two decimal places. (C = 2*pi*r)
sleet_krkn [62]

Answer:

diameter=22

circumference=22pi

Step-by-step explanation:

diameter=2*radius

so 2*11=22

circumference=2pi*r

=2*11*pi

=22pi

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3 years ago
A farmer had 17 sheep . all but 1 died. how many does the farmer have left
Ann [662]
 17- 1 = 16 sheep left
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Wewaii [24]
<span>Given that your favorite soccer team has 3 games left to finish the season and that the outcome of each game can be win, lose, or tie.

The number of possible outcomes that exist is given by 3^3=27</span>
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Challenge You buy 3.17 pounds of oranges, 1.25 pounds of pears, and 2.44 pounds of apples.
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6.86 hope this helps !! :))
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