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Firdavs [7]
2 years ago
8

(-6,-4), (3,-4) find the slope

Mathematics
1 answer:
V125BC [204]2 years ago
4 0

Answer:

Slope is 9.

Step-by-step explanation: The formula to find slope is m= y2-y1/x2-x1

-6=y1, -4=x1/ 3=y2, -4=x2

3-(-6)/-4-(-4)

=9/0=9

The Slope is 9.

I hope that this has helped, have a good day.

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Galina-37 [17]

Answer:

11y + 21

Step-by-step explanation:

mutipily 3 by y + 7 bc 3 is right outside of the parentheis which means to mutipily. Then u get 3y +21 +8y. then simpilfy

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According to data, as education level increases the unemployment rate decreases. This is an example of
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Read 2 more answers
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
Find the range of f(x) = -x + 4 for the domain (-3,-2,-1,1).
timofeeve [1]
The domain: D={-3;-2;-1; 1}

f(x) = -x + 4

subtitute

f(-3) = -(-3) + 4 = 3 + 4 = 7
f(-2) = -(-2) + 4 = 2 + 4 = 6
f(-1) = -(-1) + 4 = 1 + 4 = 5
f(1) = -1 + 4 = 3

Answer: The range: {3; 5; 6; 7}
4 0
3 years ago
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