What is the distance petween points (5,5) and (1,5) enter the units in the box

Monica has 8 more than 3 times the number of marbles Regina has.if Regina has r marbles,how many marbles does Monica have?

jarptica [38.1K]

Monica has +8(3 times (Regina))or

M=8+(3R)

8 0

3 years ago

Jennifer receives $100 and puts it into her savings account. She adds $0.25 to the account each day for a number of days, d, aft

Alona [7]

This would be A because $100 is the initial amount, and you are adding the amount that arises after (d) days. Since you are adding, it will be the sum. B says product, so you can rule it out. D says difference, so you can rule that out as well. C would be adding the days, not the amount earned each day.

4 0

3 years ago

Which of the following are exterior angles ? Check all that Apply NEED ASAP

Vika [28.1K]

Answer:

∠2 , ∠3 , ∠5 ,∠6 are exterior angles

Step-by-step explanation:

Given : Figure.

To find : Which of the following are exterior angles.

Solution : We have given a figure with angle 1 ,2, 3,4,5,6.

Exterior angle : An angle which lies outside the closed figure.

We can see ∠1 and ∠4 area lies in closed figure.

But all other angle ∠2 , ∠3 , ∠5 ,∠6 are lies outside so, these are the exterior angles.

Therefore, ∠2 , ∠3 , ∠5 ,∠6 are exterior angles

8 0

3 years ago

16. Max is sitting in the stands at the baseball stadium. He catches a

Margaret [11]

Feet, what is the angle of desperation fromax 678

4 0

3 years ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

3 years ago