3 years ago

What is the 20th term of the geometric sequence that starts with .02 and has a ratio of 2?

Mathematics

1 answer:

Jlenok [28]3 years ago

7 0

I believe the answer would be 104857.6

You might be interested in

Antwone earns money at a steady rate mowing lawns. The points (1,25) and (5,125) appear on a graph of the amount earned versus n

Volgvan

Use rise over run to find slope. If you don't know what that is, its y2-y1/x2-x1. Y2 is 125, Y1 is 25, X2 is 5, and X1 is 1. You then plug the numbers in, 125-25=100. 5-1=4. then you divide 100/4, in which you get 25. So you times 25 by 3, getting 75.

8 0

3 years ago

Ryan counts 505,515, 525, 535, 545, 555. By which number does Ryan skip count?

raketka [301]

The Anwser would se 7,363

5 0

3 years ago

Find the magnitude and direction (in degrees) of the vector. (Assume 0° ≤ < 360°.)

ddd [48]

$6i~~ + ~~2\sqrt{3}j\implies < \stackrel{a}{6}~~,~~\stackrel{b}{2\sqrt{3}} > \\\\[-0.35em] ~\dotfill\\\\ \stackrel{magnitude}{\sqrt{a^2+b^2}}\implies \sqrt{6^2+(2\sqrt{3})^2}\implies \sqrt{36+(2^2\cdot 3)}\implies \sqrt{36+12}\implies \sqrt{48} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{direction}{tan^{-1}\left( \cfrac{b}{a}\right)}\implies tan^{-1}\left( \cfrac{2\sqrt{3}}{6} \right)\implies tan^{-1}\left( \cfrac{\sqrt{3}}{3} \right) \\\\\\ tan^{-1}\left( \cfrac{1}{\sqrt{3}} \right)\implies 30^o$

3 0

2 years ago

The base of a prism is a right triangle with a base and height measurement of 12cm and a 5cm. If the volume of the prism is 210c

bezimeni [28]

Answer:

The height is 7 cm

Step-by-step explanation:

210 × 2 = 420

12 × 5 = 60

420 ÷ 60 = 7

6 0

4 years ago

Read 2 more answers

!!help!!

IrinaVladis [17]

Answer:

−

(5)(8)x

−35x+2

Step-by-step explanation:

4 0

3 years ago