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kozerog [31]
3 years ago
9

Cp=Rs6250 loss%=4% find sp​

Mathematics
1 answer:
pav-90 [236]3 years ago
4 0
Formula:
Selling price = Cost price x (1 - 4%)


Selling price:
= 6250 x (1 - 4%)

= 6250 x 96%

= 6250 x 96/100

= 6250 x 24/25

= Rs 6000

Hope it helps!
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If a 30-foot silo casts a 20-foot shadow, what is the approximate measure from the tip of the shadow to the top of the silo?
KATRIN_1 [288]

9514 1404 393

Answer:

  (d)  36 feet

Step-by-step explanation:

Use your sense of geometry.

The hypotenuse of a right triangle will never be less than the longest side, and will never be greater than 1.5 times the longest side*.

That means the only reasonable answer choices will be between 30 and 45 feet. There is only one such choice.

The measure is about 36 feet.

__

If you like, you can find a more exact value using the Pythagorean theorem. The distance d of interest is ...

  d^2 = 20^2 +30^2 = 1300

  d = √1300 = 10√13 ≈ 36.0555 ≈ 36 . . . feet

_____

* The longest hypotenuse will be √2 ≈ 1.4142 times the longest right triangle leg when the two legs are equal length.

3 0
3 years ago
The common ratio in a geometric series is 0.5 and the first term is 256. Find the sum of the first 6 terms in the series
Svetach [21]

Answer:

The sum of the first 6 terms of the series is 504.

Step-by-step explanation:

Given that,

Common ratio in a geometric series is, r = 0.5

First term of the series, a = 256

We need to find the sum of the first 6 terms in the series. If a and r area the first term and common ratio of a series, then the series becomes:

a,ar^1,ar^2,ar^3......

The sum of n terms of a GP is given by :

S_n=\dfrac{a(1-r^n)}{1-r}

Here, n = 6

S_n=\dfrac{256\times (1-(0.5)^6)}{1-0.5}\\\\S_n=504

So, the sum of the first 6 terms of the series is 504.

4 0
3 years ago
Triangle QRS is a right triangle.
adoni [48]
The answer is C.

∠STR = ∠SRQ = 90° (given) (A)
∠RST = ∠RSQ (common angle) (A)

By AA test for similarity,
∆STR is similar to ∆SRQ.
7 0
3 years ago
Read 2 more answers
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
Write a equation that is parallel to 5x-y=4
ozzi
Let's have this equation equal y first. All we have to do is add y to both sides and subtract 4 from both sides.
5x-4=y
Now, to get a parallel line, the y intercept has to change. The y intercept (the -4 in the equation) can be an infinite amount of number but -4.
Let's choose 6. We would have 5x+6=y or you could put it in the way the other equation was, 5x-y=-6.
6 0
3 years ago
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