3 years ago

How do i do this (long division)

1 answer:

7 0

Here you go u put the x-5 in the front and then the 3x^2+4x-13 in the division box, you then do 3x^2 over x to see what u get and u get 3x then u just times 3x to x-5 and then u do the same thing with the other ones and u get ur answer sorry if this isn't that helpful

You might be interested in

What is the value of x? O 13 O 14 O 26 O 28

BartSMP [9]

It’s A. 13

hope this helps

7 0

2 years ago

Pls help!!

Allisa [31]

Answer:

Perimeter = 17a

Area = 30 square meters

Step-by-step explanation:

Perimeter = 2b + 8 = 10b + 5 + a = 15ab + 2a - b = 17a

Area = 2 + 8 = 10 + 2 = 12 × 5 = 60 simplify

I honestly don't know if this is correct, I hope it is

8 0

2 years ago

Read 2 more answers

Can you answer this Algebra question please?<br> (Just A, thank you).

Eduardwww [97]

$d_f=d_i+v_0t+\dfrac{1}{2}at^2 \\d_f-d_i-\dfrac{1}{2}at^2=v_0t \\v_0=\boxed{\dfrac{d_f+d_i-\frac{1}{2}at^2}{t}} \\$

Hope this helps.

8 0

3 years ago

Read 2 more answers

A gift shop sells 140 wind chimes per month at $90 each. The owners estimate that for each $5 increase in price, they will sell

guapka [62]

Answer: $95

Step-by-step explanation:

Te new price will be 90 + 5x, if the price increases "x" times

The number of wind chimes sold per month will become 140 - 7x

$\begin{aligned}&\text {Revenue, } \mathrm{R}(\mathrm{x})=(90+5 \mathrm{x})(140-7 \mathrm{x}) \\&R^{\prime}(x)=5(140-7 x)-7(90+5 x) \\&R^{\prime}(x)=700-35 x-630-35 x \\&R^{\prime}(x)=70-70 x=0 \\&70 x=70 \\&x=1\end{aligned}$

Therefore, if the price becomes (90 + 5(1)) = $95 per wind chime, then the revenue will be maximum

6 0

2 years ago

A theatre ticket costs £63 plus a booking fee of 3% what is the total price of the ticket

ryzh [129]

P=63+63(3/100)

p=63(1+3/100)

p=63(1.03)

p=$64.89

6 0

3 years ago