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dezoksy [38]
3 years ago
10

What is an equation of a line perpendicular to 5x+8y=16 and passed through (-5,7)

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer:

y = (8/5)x + 15

Step-by-step explanation:

<em>First change the equation to standard form (y=mx+b)</em>

5x + 8y = 16

8y = 16 - 5x

y = - (5/8)x + (16/8)

y = - (5/8)x + 2

<em>Perpendicular Lines have the inverse opposite sign of slope</em>

<em>[For example: inverse opposite sign of 2 is - (1/2)]</em>

Original equation slope (m) : - (5/8)

2nd Equation (m) : 8/5

<em>After finding the slope, plug in the slope and points the standard form equation (y=mx+b)</em>

Point: (-5,7)     x : -5     y : 7

Slope (m) : 8/5

y = m x + b

7 = (8/5) (-5) + b

<em>'b' is the y-intercept and the last thing to solve for the equation</em>

7 = - 8 + b

15 = b

<em>Now, put the slope (m) and y-intercept (b) back into the equation</em>

y = (8/5)x + 15

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