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lana66690 [7]
3 years ago
13

What is the constant in the mathematical expression?

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0
1.1+2+7+25+1.1+2+2 and rhat is the expression
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The area under a particular normal curve between 6 and 8 is 0.695. A normally distributed variable has the same mean and standar
TiliK225 [7]

Answer:

69.5%

Step-by-step explanation:

A feature of the normal distribution is that this is completely determined by its mean and standard deviation, therefore, if two normal curves have the same mean and standard deviation we can be sure that they are the same normal curve. Then, the probability of getting a value of the normally distributed variable between 6 and 8 is 0.695. In practice we can say that if we get a large sample of observations of the variable, then, the percentage of all possible observations of the variable that lie between 6 and 8 is 100(0.695)% = 69.5%.

4 0
3 years ago
3/5x = -15 one or two step equations
Ronch [10]

Answer:

x=1/25

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha
hodyreva [135]

Answer:

11196.15 km

Step-by-step explanation:

Consider the attached diagram

If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.

Using trigonometry

Tan \alpha =\frac{Opposite}{adjacent} \\Tan 15 =\frac{3000}{|AB|}

Cross multiply

|AB|X Tan 15 =3000

|AB| = \frac{3000}{Tan 15} =11196.15 km

Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km

6 0
3 years ago
The results of a poll show that the true proportion of students who prefer the new schedule is likely in the interval (0.195,0.2
KengaRu [80]

Answer:

0.22

Step-by-step explanation:

The point estimate is simply the middle of the confidence interval.

p = (0.195 + 0.245) / 2

p = 0.22

3 0
3 years ago
1. Circles and segments create the many relationships addressed in the theorems throughout this unit. Use those theorems and the
jeyben [28]
(a) m<IJK = 90 since segment IK is a diameter
(b) KI = 10 since since LM = KM = KI = 5. The 3 segments are radii.
(c) EP * PL = OP * PF; EP = 2
(d) m<OFH = 178/2 = 89; inscribed angle is half measure of intercepted arc
8 0
3 years ago
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