Ask question

Ask question

All categories

Ilia_Sergeevich [38]

3 years ago

10

You roll a 15-sided die (having the numbers 1-15 on it). What is the probability that the value of the roll will be a multiple o

f 3.

2 answers:

aev [14]3 years ago

3 0

Answer:

1/5

Step-by-step explanation:

Levart [38]3 years ago

3 0

Answer:

1 over 5

Step-by-step explanation:

You might be interested in

If jefferson had 337 and he mulpied it wit 90 how many would he have?!

Aleks04 [339]

Answer:

337x90=30330 simple multiplication:) Hope this helped!

4 0

3 years ago

Read 2 more answers

Let c be the path c(t) = (2t, t2, log(t)), defined for t > 0. find the arc length of c between the points (2, 1, 0) and (12,

V125BC [204]

The path starts at $t=1$ and ends at $t=6$ , so we have an arc length of

$\displaystyle\int_{\mathcal C}\mathrm dS=\int_{t=1}^{t=6}\|\mathbf c'(t)\|\,\mathrm dt$
$=\displaystyle\int_1^6\sqrt{2^2+(2t)^2+\left(\frac1t\right)^2}\,\mathrm dt$
$=\displaystyle\int_1^6\sqrt{4t^2+4+\frac1{t^2}}\,\mathrm dt$
$=\displaystyle\int_1^6\frac1t\sqrt{4t^4+4t^2+1}\,\mathrm dt$
$=\displaystyle\int_1^6\frac1t\sqrt{(2t^2+1)^2}\,\mathrm dt$
$=\displaystyle\int_1^6\frac{2t^2+1}t\,\mathrm dt$
$=\displaystyle\int_1^6\left(2t+\frac1t\right)\,\mathrm dt$
$=t^2+\log t\bigg|_{t=1}^{t=6}$
$=(6^2+\log6)-(1^2+\log1)=35+\log6$

4 0

4 years ago

2. Solve for x in the triangle shown below.

Free_Kalibri [48]

Answer:

The answer D) because you add the same variable's which leave you with 2x-4

Step-by-step explanation:

first do positive 7-4-1=2. after that do the variables which get you 2x+1x+1x=4x

6 0

3 years ago

Read 2 more answers

Sarah begins at a negative position along the x-axis. Sarah moves in the positive x-direction, turns around and then moves in th

a_sh-v [17]

Answer:

he magnitude of Sarah's displacement is less than the distance she travels

Step-by-step explanation:

Hi!

The magnitude of her displacement is just the difference between her final and initial state, however the distance she traveled is two times the distance she moved in the positive x-direction until she turned around, since she had to move back, plus her displacement.

So:

$displacement = |x_{final} -x_{initial}| \\distanceTraveled = 2|x_{return}-x_{initial}| + displacement\\$

Since all the terms are positive:

$x_{displacement}$

3 0

3 years ago

Take these points for free have a nice day bye!

kap26 [50]

Answer: Have A Blessed Day!

Step-by-step explanation:

Thanks you! Have a nice day!

7 0

3 years ago

Read 2 more answers