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nirvana33 [79]
3 years ago
13

Whats the equation for 4n + 6 - 2n= 2 (n+3)

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0
4n + 6 - 2n = 2(n + 3)

Simplify.

4n + 6 - 2n = 2n + 6

Subtract 6 from both sides.

4n - 2n = 2n + 6 - 6

Subtract 2n from both sides.

4n - 2n - 2n = 6 - 6

Simplify.

0 = 0

Therefore, there are infinite solutions.

~Hope I helped!~
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1. Which are true of x = log10 31,500? Select all that apply.
ziro4ka [17]

Given:

x=\log_{10}31,500

To find:

Select the true statements from the given options about the given value.

Solution:

We have,

x=\log_{10}31,500

It can be written as

x=\log_{10}(2^23^25^37)

x=\log_{10}(2^2)+\log_{10}(3^2)+\log_{10}(5^3)+\log_{10}(7)     [\because \log(ab)=\log a+\log b]

x=2\log_{10}2+2\log_{10}3+3\log_{10}5+\log_{10}(7)

x=2\left(0.30105\right)+2\left(0.47712\right)+3\left(0.69897\right)+0.8451

x=4.49835

Clearly, the value of x lies between 4 and 5. So, x>4 and x.

Therefore, the correct options are C and D.

4 0
3 years ago
Please help me on this
Lana71 [14]
It may be the last one......................................... but i'm not sure.
5 0
3 years ago
Solve the inequality 3 - 5(2x + 1) ≤ 10.
Rus_ich [418]
3-5(2x+1) < 10
3-10x-5<10
-10x-2<10
-2<10+10x
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5 0
3 years ago
Read 2 more answers
Identify the rule for the following pattern:<br> 99, 90, 81...
PilotLPTM [1.2K]
The pattern is subtracting 9
5 0
3 years ago
Suppose a researcher is estimating the proportion of trees showing signs of disease in a local forest. They randomly sample 150
Serhud [2]

Answer:

0.167 - 1.96 \sqrt{\frac{0.167(1-0.167)}{150}}=0.107

0.167 + 1.96 \sqrt{\frac{0.167(1-0.167)}{150}}=0.227

And the 95% confidence interval would be given (0.107;0.227).

Step-by-step explanation:

Information given

X= 25 number of trees with signs of disease

n= 150 the sample selected

\hat p=\frac{25}{150}= 0.167 the proportion of trees with signs of disease

The confidence interval for the true proportion would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the significance is \alpha=1-0.95=0.05 and \alpha/2=0.025, and the critical value would be

z_{\alpha/2}=1.96

And replacing we got:

0.167 - 1.96 \sqrt{\frac{0.167(1-0.167)}{150}}=0.107

0.167 + 1.96 \sqrt{\frac{0.167(1-0.167)}{150}}=0.227

And the 95% confidence interval would be given (0.107;0.227).

6 0
3 years ago
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