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Olin [163]
2 years ago
13

1. Which are true of x = log10 31,500? Select all that apply.

Mathematics
1 answer:
ziro4ka [17]2 years ago
4 0

Given:

x=\log_{10}31,500

To find:

Select the true statements from the given options about the given value.

Solution:

We have,

x=\log_{10}31,500

It can be written as

x=\log_{10}(2^23^25^37)

x=\log_{10}(2^2)+\log_{10}(3^2)+\log_{10}(5^3)+\log_{10}(7)     [\because \log(ab)=\log a+\log b]

x=2\log_{10}2+2\log_{10}3+3\log_{10}5+\log_{10}(7)

x=2\left(0.30105\right)+2\left(0.47712\right)+3\left(0.69897\right)+0.8451

x=4.49835

Clearly, the value of x lies between 4 and 5. So, x>4 and x.

Therefore, the correct options are C and D.

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Someone please help me on number 3 and if the others are wrong please let me know ITS MULTI STEP EQUATION COMBINING LIKE TERMS
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Answer:

#1: x = 3; #2 c = 1/2; #3 = x = 22; #4 is correct (x = -8)

Step-by-step explanation:

for the first equation everything was right until 22x = 66

after

22x = 66

you must divide everything by 22

x = 3

that is for #1

for the second equation you copied down the question wrong

the negative is still there

6c - 8 - 2c = -6

combine 6c and -2c

4c - 8 = -6

the negative remains on the 8

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now divide both sides by -2

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number four should be correct

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