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Olin [163]
2 years ago
13

1. Which are true of x = log10 31,500? Select all that apply.

Mathematics
1 answer:
ziro4ka [17]2 years ago
4 0

Given:

x=\log_{10}31,500

To find:

Select the true statements from the given options about the given value.

Solution:

We have,

x=\log_{10}31,500

It can be written as

x=\log_{10}(2^23^25^37)

x=\log_{10}(2^2)+\log_{10}(3^2)+\log_{10}(5^3)+\log_{10}(7)     [\because \log(ab)=\log a+\log b]

x=2\log_{10}2+2\log_{10}3+3\log_{10}5+\log_{10}(7)

x=2\left(0.30105\right)+2\left(0.47712\right)+3\left(0.69897\right)+0.8451

x=4.49835

Clearly, the value of x lies between 4 and 5. So, x>4 and x.

Therefore, the correct options are C and D.

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Step-by-step explanation:

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3 years ago
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2 years ago
6/10+6/100= how do i do this problem
olya-2409 [2.1K]

Answer:

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Step-by-step explanation:

As division is always done before addition you would divide the 6 by 10 and then divide the 6 by 100. 6 divided by 10 is equal to 0.6 as you move the decimal point to the left once. 6 divided by 100 is equal to 0.06 as you move the decimal point to the left twice. Addition is always done after division so you would add 0.6 and 0.06 together. This will give you 0.66 as your answer.

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3 years ago
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PtichkaEL [24]
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7 0
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Answer:

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Step-by-step explanation:

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