Quadrilateral ABCD is a square and the length of BE¯¯¯¯¯ is 6 cm.
2 answers:
Answer: AC= 12 cm
Step-by-step explanation:
Here, ABCD is a square with diagonals AC and BD.
Let E is the intersection point of Diagonals AC and BD.
Since, we know that the lengths of diagonals of a square are same.
Therefore We can say, AC=BD
And we know that,
In the case of square diagonals bisect each other,
That is, BE=ED⇒BD= 2BE.
But, BE= 6 cm (given)
⇒BD=12 cm ⇒AC= 12 cm
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Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore,
⇒
⇒
⇒
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
