The angle opposite of the 27° one would also be 27° because vertically opposite angles are congruent
The other two angles would be 180°-27° which =153°
This is because co-interior angles (allied angles) are supplementary.
Supplementary means that they add up to 180°.
Please give me brainliest answer! If you have any questions, just ask!
How many truckloads will be left after 2 days?
Answer: 30 truckloads
Multiply 8 by 2.
8(2)
16
Then 46 minus 16
46-16=30 truckloads
After 3 days?
Answer: 22 truckloads
Multiply 8 by 3
8(3)
24
Then 46 minus 24
46-24=22 truckloads
When will more need to be ordered?
Answer: 4 days
Find the closest # to 46 that's a multiple of 8 and has more than 16 left over:
8,16,24,32,40,48
40 is the closest, but has more than 16 leftovers. So the next one would be 32. If you subtract 32 from 48, you have exactly 16 left. 32 is the 4th multiple of 8, so there would be 4 days until they need a refill.
Answer:
Michael took his 6th sip at 4 : 05
Step-by-step explanation:
Duration in which Michael takes a sip of water = 20 minutes
Therefore, he will take his sixth sip after (20 × 6) = 120 minutes Or after 2 hours
If he takes first sip of water at 3 : 05
Then he will take his sixth sip at ( 3 : 05 + 2 : 00)
Time at his sixth sip = 5 : 05
Whats the question? we cant help you if you dont give us the question.
Given:
f(x) is an exponential function where f(3) = 18 and f(7.5) = 60.
To find:
The value of f(12), to the nearest hundredth.
Solution:
Let the exponential function be
...(i)
It is given that
. Substitute
in (i).
![f(3)=ab^3](https://tex.z-dn.net/?f=f%283%29%3Dab%5E3)
...(ii)
It is given that
. Substitute
in (i).
![f(7.5)=ab^{7.5}](https://tex.z-dn.net/?f=f%287.5%29%3Dab%5E%7B7.5%7D)
...(iii)
Divide (iii) by (ii).
![\dfrac{10}{3}=b^{4.5}](https://tex.z-dn.net/?f=%5Cdfrac%7B10%7D%7B3%7D%3Db%5E%7B4.5%7D)
Putting
in (ii), we get
![18=a(1.30676)^3](https://tex.z-dn.net/?f=18%3Da%281.30676%29%5E3)
![\dfrac{18}{(1.30676)^3}=a](https://tex.z-dn.net/?f=%5Cdfrac%7B18%7D%7B%281.30676%29%5E3%7D%3Da)
![a\approx 8.0665](https://tex.z-dn.net/?f=a%5Capprox%208.0665)
Putting
and
in (i), we get
![f(x)=8.0665(1.30676)^x](https://tex.z-dn.net/?f=f%28x%29%3D8.0665%281.30676%29%5Ex)
Putting x=12, we get
![f(12)=8.0665(1.30676)^{12}](https://tex.z-dn.net/?f=f%2812%29%3D8.0665%281.30676%29%5E%7B12%7D)
![f(12)=200.0024](https://tex.z-dn.net/?f=f%2812%29%3D200.0024)
![f(12)\approx 200.00](https://tex.z-dn.net/?f=f%2812%29%5Capprox%20200.00)
Therefore, the value of f(12) is about 200.00.