Question

Solve each system by elimination. Check the solution in both of the original equations.

Answer 1

Answer:

After finding the solution of given equations by elimination method

-3x-3y=12

-9x+3y=-24

we get the value of x=1 and y= -5

Step-by-step explanation:

$-3x-3y=12$ is eq A

$-9x+3y= -24$ is eq B

To find out value of x and y we will use elimination method

To find value of x add eq A and eq B

$(-3x-3y)+ (-9x+3y)= 12 + (-24)\\-3x-3y-9x+3y= 12-24\\-12x = -12\\dividing \,\,by -12\,\,on\,\, both\,\,sides\\\frac{-12x}{-12} = \frac{-12}{-12} \\x= 1$

Now to find value of y put x=1 in eq A

$(-3 \times 1 )- 3 y=12\\-3 -3y =12\\\\adding\,\,3\,\,on\,\, both\,\,sides\\-3y=12+3\\\\dividing\,\,-3\,\,on\,\,both\,\,sides\\y= \frac{15}{-3} \\y= -5$

so the value of

x= 1

and

y= -5

For checking the solution

putting value of x and y in eq A

$-3x-3y=12\\-3(1)-3 (-5)=12\\-3+15=12\\12=12$

Hence proved

Putiing value of x and y in eq B

$-9x+3y= -24\\-9(1) + 3 (-5) = -24\\-9 -15 = -24\\-24= -24$

Hence proved

Keywords: Solving Linear System

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