First, I thought this was a trick question and maybe it is, but I say the answer is 110
Answer:
P(1) = 1 - 8/27 = 19/27
The probability that at least one of them will be elected is 19/27
Step-by-step explanation:
the probability that at least one of them will be elected = 1 - probability that none of them will be elected.
P(1) = 1 - P(None) .....1
Let P(A), P(B) and P(C) represent the probability for each of the three candidates to be elected .
P(A) = P(B) = P(C) = 1/3
The probability for each of the three candidates not to be elected is
P(A)' = P(B)' = P(C)' = 1 - 1/3 = 2/3
P(None) = P(A)' × P(B)' × P(C)'= 2/3 × 2/3 × 2/3 = 8/27
From equation 1. Substituting the value of P(None)
P(1) = 1 - 8/27 = 19/27
The probability that at least one of them will be elected is 19/27
Answer:
d) last bottom picture
Step-by-step explanation:
This shape has 4 boxes and two are shaded. So, it means the fraction of 2/4. Hence, option (d) is the correct answer.
Answer:
1. x = 5x + 16
x=−4
2.(-5x) + 2 = 4x + 29
x=−3
3.5x = (-5x) - 10
x=−1
4.(-2x) + 1 = 3x + 11
x=−2
Step-by-step explanation:
Answer:
y = x'
z = y'
z' = x + t
Step-by-step explanation:
Hi!
You need to define two new variables y and z:
y = x'
z = y'
Then:
z = y' = x''
z' = x''' = x + t
Now you have a system of 3 equations with only first derivatives