Answer:
4<C
<10
Step-by-step explanation:
Theorem: Given a triangle with sides A, B and C the sum of the lengths of any two sides of a triangle must be greater than the third side:
1. A+B>C
2. B
+C
>A
3. A+C>B
Thus given two sides of A=3 and B=7 C can be:
7
−3<C
<
7+3
C range
4<C
<10
Answer:
C. 8, 11, 12, 13, 3, 8, 16, 13, 10
Step-by-step explanation:
If you put those in order least to greatest, least is 3, greatest is 16, median is 11, q1 is 8, and q3 is 13, which is what is displayed on the box plot
f(x, y) = 4x + 7y - 6
substitute x=5 and y=-5
f(5,-5) = 4(5) + 7(-5) - 6
f(5,-5) =20-35-6
= -15-6
=-21
Answer:third option
Step-by-step explanation:
I just did it
Answer:
75
Step-by-step explanation:
Divide 50 by 2/3. Division is the same as asking "how many times can i subtract 2/3 from 59?"
Dividing by a fraction is the same as multiplying by the reciprocal.
You can subtract 2/3 from 50, 75 times
