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galben [10]
2 years ago
12

What are the new coordinates of (10,3) reflected along the x axis?

Mathematics
1 answer:
Anon25 [30]2 years ago
7 0

Answer:

(10,-3)

Step-by-step explanation:

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I will mark as brainliest, thank you
ch4aika [34]

It would be 3/25 who are left handed and 22/25 who are right handed.

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3 years ago
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Write 26 5/6<br> as a decimal.
fomenos

Answer:

26.8<u>3</u>

Step-by-step explanation:

5/6=0.83333 repeating

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3 years ago
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Barry wants to take out a loan from his bank for $1,000 to buy a bicycle. The interest rate on the loan from the bank is 9%. He
tekilochka [14]

Answer:

The amount that Barry would pay in interest for his loan is $15.05.

Step-by-step explanation:

To calculate this, we first calculate the monthly required fixed payment using the formula for calculating loan amortization as follows:

P = (A * (r * (1 + r)^n)) / (((1+r)^n) - 1) .................................... (1)

Where,

P = Monthly required fixed payment = ?

A = Loan amount = $1,000

r = monthly interest rate = 9% / 12 = 0.09 / 12 = 0.0075

n = number of payment months = 3

Substituting all the figures into equation (1), we have:

P = ($1,000 * (0.0075 * (1 + 0.0075)^3)) / (((1 + 0.0075)^3) - 1)

P = $338.35

Therefore, we have:

Total repayment = P * 3 months = $338.35 * 3 = $1,015.05

Interest amount = Total repayment - Loan principal = $1,015.05 - $1,000 = $15.05.

Therefore, the amount that Barry would pay in interest for his loan is $15.05.

3 0
2 years ago
Describe and correct the error in determining wheather (8,11) is a solution of y-x=3
Burka [1]

(8, 11) is the correct solution. x = 8, y = 11

Plug it in:

11-8=3

That's correct.

7 0
3 years ago
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Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

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Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
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