Answer:
Algebraic expressions are useful because they represent the value of an expression for all of the values a variable can take on
Answer:
B.7
Step-by-step explanation:
This one is pretty simple, just insert each number to find which one is true.
2(7)<18
14< 18 (true)
2(9) < 18
18< 18 (false because it said less than not less than or equal to)
2(36) < 18
72< 18 (false)
Answer:
-2/3
Step-by-step explanation:
Log125(1/25)=x
Raise each side to the base of 125
125^Log125(1/25)=125^x
1/25 = 125^x
Rewrite 25 as a power of 5 and 125 as a power of 5
1 / 5^2 = 5^3^x
The if power is in the denominator, we can bring it to the numerator by making it negative
5^-2 = 5^3^x
We know that a^b^c = a^(b*c)
5^-2 = 5^(3*x)
Since the bases are the same, the exponents are the same
-2 = 3x
Divide by 3
-2/3 = 3x/3
-2/3 =x
The formula is
A=p (1+rt)
A future value 1249.22
P present value ?
R interest rate 0.14
T time 1 year
We need to solve for p
P=A÷(1+rt)
P=1,249.22÷(1+0.14×1)
P=1,095.81 round your answer
P=1096
Hope it helps
Answer:
C. 0
Step-by-step explanation:
When adding a negative number, you are just subtracting
So, 8 - 8=0
