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harina [27]
3 years ago
6

Suppose the height of a cylinder is equal to its radius. the cylinder can fit inside a square prism, as shown below. the cross-s

ectional areas are still the same and the ratio of the area of the circle to the area of the square is still . complete the derivation of the formula for a cylinder whose height is equal to its radius. the prism's volume is the area of the base, , times the height, . since the ratio of the areas is , then the volume of the cylinder is times the volume of the prism. v
Mathematics
2 answers:
natulia [17]3 years ago
5 0

Answer:

1. 2r(2r)

2. r

3. pi/4

4. pi times r cubed

Step-by-step explanation:

Liono4ka [1.6K]3 years ago
3 0

1. 2r(2r)

2. r

3. pi/4

4. pi times r cubed

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Which choices are equivalent to the expression below? Check all that apply.<br> 3sqrt8
Serga [27]
It is C, D and F

-/72
3 0
2 years ago
Brian flips a fair coin 3 times. What is the probability of getting exactly 1 tail?
Leya [2.2K]

Answer:

1/3

Step-by-step

he flips the coin three time and there is one side so 1/3

3 0
3 years ago
PLZ HELP! MAAAATH! image attached
Elena L [17]

c(f) =  \frac{5}{9} (f - 32)
4 0
3 years ago
Pleasssseeee hellllpllllllppppp???????
olchik [2.2K]

Answer:

f(x) and g(x) are inverse functions

Step-by-step explanation:

In the two functions f(x) and g(x) if, f(g(x)) = g(f(x)) = x, then

f(x) and g(x) are inverse functions

Let us use this rule to solve the question

∵ f(x) = 3x²

∵ g(x) = \sqrt{\frac{x}{3}}

→ Find f(g(x)) by substitute x in f(x) by g(x)

∴ f(g(x)) = 3(\sqrt{\frac{x}{3}})²

→ Cancel the square root with power 2

∴ f(g(x)) = 3(\frac{x}{3})

→ Cancel the 3 up with the 3 down

∴ f(g(x)) = x

→ Find g(f(x)) by substitute x in g(x) by f(x)

∴ g(f(x)) = \sqrt{\frac{3x^{2}}{3}}

→ Cancel the 3 up with the 3 down

∴ g(f(x)) = \sqrt{x^{2}}

→ Cancel the square root with power 2

∴ g(f(x)) = x

∵ f(g(x)) = g(f(x)) = x

→ By using the rule above

∴ f(x) and g(x) are inverse functions

5 0
2 years ago
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
2 years ago
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