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ra1l [238]
3 years ago
7

Find the area of shaded sector of the circle?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0
Tutu bskdnb dhdbdvrnir
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inessss [21]

Answer:

no

Step-by-step explanation:

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7 0
3 years ago
The ratio of sodas to days is 1 to 5. How<br> many sodas would you get in 30 days?
8_murik_8 [283]

Answer:

6

Step-by-step explanation:

7 0
3 years ago
Consider the following.
Olin [163]

Answer:

Step-by-step explanation:

f(t) = t + cos(t)

Criticals :

f' (t) = 1 - sin (t) = 0

sin (t) = 1

Given that the interval is : [ - 2π , 2π ]

thus;  t = π/2 and -3π/2

The region then splits into [ -2π , -3π/2 ], [-3π/2 , 2π ]  and [ π/2 , 2π ]

Region 1:                            Region 2:                         Region 3:

[ -2π , -3π/2 ]                      [-3π/2 , 2π ]                      [ π/2 , 2π ]

Test value (t): -11 π/6          Test value(t) = 0              Test value = π

f'(t) = 1 - sin(t)                       f'(t) = 1 - sin(t)                   f'(t) = 1 - sin(t)

f'(t) = 1 - sin (-11 π/6)            f'(t) = 1 - sin (0)                  f'(t) = 1 - sin(π)

f'(t) =  positive value           f'(t) = 1 - 0                         f'(t) = 1 - 0.0548

thus; it is said to be            f'(t) = 1  (positive)              f'(t) = 0.9452 (positive)

increasing.                          so it is increasing            so it is increasing

So interval of increase is :  [ -2π , 2π ]

There is no  local maximum value or minimum value since the function increases monotonically over [ -2π , 2π ]. Hence, there is no change in the pattern.

c) Inflection Points;

Given that :

f'(t) = 1 - sin (t)

Then f''(t) = - cos (t) = 0

within [ -2π , 2π ], there exists 4 values of  t for which costs = 0

These are:

[-3π/2 ]

[-π/2 ]

[π/2 ]

[3π/2 ]

For Concativity:

This splits the region into [ -2π , -3π/2], [ -3π/2 ,  -π/2], [-π/2 , π/2] , [π/2 , 3π/2] and [ 3π/2 , 2π].

Region 1: [ -2π , -3π/2]      Region 2: [ -3π/2 ,  -π/2]            

Test value = - 11π/6           Test value = π                            

f''(t) = - cos (t)                      f''(t) = - cos (t)

- cos (- 11π/6) = negative    f''(-π) = - cos (- π)

Thus; concave is down.      f''(π) = -cos (π)

                                           positive, thus concave is up

Region (3):   [-π/2 , π/2]

Concave is down

Region (4):  [π/2 , 3π/2]

Concave is up

Region (5):  [ 3π/2 , 2π]

Concave is down

We conclude that:

Concave up are at region 2 and 4:  [ -3π/2 ,  -π/2] ,  [π/2 , 3π/2]

Concave down are at region 1,3 and 5 :  [ -2π , -3π/2] , [-π/2 , π/2] , [ 3π/2 , 2π]

6 0
3 years ago
sue's tyre pressure gauge shows a reading which is 8 percent higher than the actual pressure. What is the actual pressure when s
MatroZZZ [7]

Answer: 36.5

Step-by-step explanation:

39.42=(100%+8%)=108%

x=100%

39.42/x = 108/100

x=39.42*100/108

x=36,5

actual pressure will be 36,5

4 0
2 years ago
How do you write a linear function
bazaltina [42]

1. Start out with y=mx+b. 'm' is the slope and 'b' is the y intercept.

2. Find where the line hits the y-axis on the graph. This will be your Y-Intercept.

3. Find where your line hits the X-axis. Now, count up or down from the x-axis until you get to the height of the y-point. now count across. Down/Up Divided by Across. This is your slope.

For Example, say that the line hits the Y-Axis at 4, and the line hits the X-Axis at -8. Count up from -8 till you get to the height of 4. It is 4. Now count across from that height. It is 8. Now, just put 4 on top of 8, to get 4/8. Simplify to 1/2. That is your slope. And since the line hit the Y-Axis at 4, 4 would be your Y-Intercept. Your final formula would be:

y=1/2x+4

8 0
3 years ago
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