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guajiro [1.7K]
3 years ago
8

Divide 60kg in the ratio 5:7

Mathematics
1 answer:
snow_lady [41]3 years ago
8 0

Step-by-step explanation:

Hey there!!

Given, The ratio is: 5:7

Let x be a common factor.

Now,

5x+7x = 60

12x = 60

x =  \frac{60}{12}

Therefore, x= 5.

5x = 5×5 = 25.

7x= 7×5=35.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

You might be interested in
What is 13/2 - 2/13.
skad [1K]
13/2 = 6.5
2/13 = 015
6.5-0.15 = 6.35
4 0
3 years ago
The line through (-1/2, -7/2) and (2, 14) in slope intercept form??
icang [17]
To find the equation of a line in slope-intercept form given two points, we must arrange the points this way to find the slope (m):

m =  \frac{y_{2}-y _{1}}{x_{2}-x_{1}}

We can replace the variables in this equation with the values from the points we have been given, (\frac{-1}{2},  \frac{-7}{2}) and (2, 14). We know that the x-values always come first in an ordered pair, so we can put those in our equation first.
It doesn't really matter which x-value goes in which x-value slot in the equation as long as you match up the y-values in the same fashion. But for the sake of convenience, we will call the 2 in the second ordered pair x_{2} and the \frac{-1}{2} in the first ordered pair x_{1}.
Now, we can match these values in our equation, and while we're at it, we can substitute the appropriate y-values into their places as well.

m =  \frac{y_{2}-y _{1}}{x_{2}-x_{1}}

m =  \frac{14 -  \frac{-7}{2} }{2 -  \frac{-1}{2} }

Now, we can see that we are subtracting negatives in this equation. Remember that whenever you subtract a negative, it is the same as adding a positive. So, this equation could be rewritten as

m =  \frac{14 +  \frac{7}{2} }{2 +  \frac{1}{2} }

and we can change the improper fraction in the numerator into a mixed number for ease of addition.

m =  \frac{14 + 3 \frac{1}{2} }{2+ \frac{1}{2} }

And here, we can add, since it's made simple for us.

m =  \frac{17  \frac{1}{2} }{2  \frac{1}{2} }

Finally, to get the slope we can complete the fraction by dividing.

17.5 ÷ 2.5 = 7

The slope of this equation, m, is 7, and so far, our equation looks like this:

y = 7m + b

Now, to find y-intercept.

To do this, we simply have to substitute one of the ordered pairs in for the appropriate x- and y-values and solve. To make it easier on ourselves, we can use (2, 14) so we don't have to deal with negative numbers or fractions.

y = 7x + b

Let us substitute in our values.

14=7(2)+b

Now, we can solve by multiplying the 7 and 2.

14=14+b

Here, we can subtract 14 from both sides, since it is added to both in the equation, and we are left with

0 = b

which can be flipped around to show

b=0

The y-intercept of this line is 0.

Now, we can make this known in our equation like this:

y=7x+0

Or, for neatness' sake, we can just say

y=7x

which is your final equation.

The line through (\frac{-1}{2},  \frac{-7}{2}) and (2, 14) in slope-intercept form is <span>y=7x.
Hope that helped! =) </span>


7 0
3 years ago
HELP me plz someone!
Kamila [148]

Answer:

4,095 ft³

Step-by-step explanation:

V=LWH

V = 3 x 15 x 14

V= 4,095

4 0
3 years ago
5/x - 3/4 =<br> Simplify
Verdich [7]

Answer:

\frac{20-3x}{4x}

Step-by-step explanation:

-This is an LCM problem.

-To simplify, we introduce a least common multiplier which is equivalent the product of the denominators:

LCM=x\times 4\\\\=4x

#We introduce the LCM and adjust the fractions based on it :

=\frac{5}{x}+\frac{3}{4}\\\\\\=\frac{20}{4x}+\frac{3x}{4x}\\\\\\=\frac{20-3x}{4x}

Hence, the simplified form of the fraction is: \frac{20-3x}{4x}

7 0
3 years ago
Perform the indicated row operations, then write the new matrix.
Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]

Operations:

2R_1 + R_2 ->R_2

-3R_1 +R_3 ->R_3

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

Step-by-step explanation:

The first operation:

2R_1 + R_2 ->R_2

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by 2

2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}0&5&7|1\end{array}\right]

The second operation:

-3R_1 +R_3 ->R_3

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by -3

-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]

Hence, the new matrix is:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

3 0
3 years ago
Read 2 more answers
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