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3 years ago

What is 3+3/-4+6-34+9

Mathematics

2 answers:

boyakko [2]3 years ago

8 0

Answer:

-67/4 or -16.75

Step-by-step explanation:

Simply plug all of that into the calc and you should get your answer.

vitfil [10]3 years ago

5 0

ANSWER:

The answer is -16.75

First divide the division 3/-4 then start the addition and subtraction

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2 years ago

Please help stupidboythink or anybody

SashulF [63]

Answer: what's the question?

Step-by-step explanation:

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2 years ago

Read 2 more answers

Help and explanation.

Natasha_Volkova [10]

Answer:

Andrew

Step-by-step explanation:

Abby:

Since red cards are negative, a red 9 would represent the number -9. And because black cards are positive, a black 6 would represent the number 6. To get the sum, we add the two numbers together:

-9 + 6

That gives us a total of -3.

Ashley:

We can do the same thing as before. A black seven would represent 7 and a red 8 would represent -8. Next we again add them together:

7 + (-8)

That gives us a total of -1.

Andrew:

The red 4 is -4, while the black 4 is 4:

-4 + 4

That gives us a total of 0.

Anna:

Anna has a red 8 which represents -8 and another red, a three, which would represent -3. We can add the two to get:

-8 + (-3)

That gives us a total of -11.

In all, Andrew has the highest sum of 0, which means he won the game.

6 0

2 years ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

2 years ago