The correct solution would be D.(9,3)
Answer:
Margret is correct, Kevin is wrong.
Step-by-step explanation:
6^-4 can be written as (1/6)^4
By taking (1/6)^5 times you have (1/6)(1/6)(1/6)(1/6)(1/6), multiplying by 6 would cancel one of those (1/6ths) out. Meaning you would be left with (1/6)^4 or 6^-4
Kevin is wrong because taking 6^4 would not be the same as 6^-4, 6^4= 1296, multiplying that by 1/6 would not give you the same value as 6^-4. His mistake was that he did not take the reciprocal of 6^-4 and incorrectly removed a negative.
Hope this helps, for more assistance please check out: http://linktr.ee/x.squared/
Answer:
To add or subtract functions, just add or subtract the values at each point where it makes sense. If the functions are given by formulas, you can just add or subtract the formulas (it doesn't matter whether you plug in values before or after).
Answer:
(3r-10) (r+8)
Step-by-step explanation:
3r-34r+80
The first step is to combine like terms
3r - 34r
is -31r
-31r+80
We cannot factor since 31 is a prime number and 80 is not a multiple of 31
If you mean
3r^2-34r+80
(3r-10) (r+8)
Answer:
about 5 years 6 months
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 5%/100 = 0.05 per year,
then, solving our equation
t = 178.25 / ( 650 × 0.05 ) = 5.4846
t = 5.4846 years
The time required to
accumulate simple interest of $ 178.25
from a principal of $ 650.00
at an interest rate of 5% per year
is 5.4846 years (about 5 years 6 months).
