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brilliants [131]
3 years ago
12

What is the value of x in the equation 1.5(x + 4) - 3 = 4.5(x - 2)?

Mathematics
2 answers:
sergeinik [125]3 years ago
6 0

Answer:

x = 3

Step-by-step explanation:

Nata [24]3 years ago
3 0

Answer:

x=4

Step-by-step explanation:

1.5(x + 4) - 3 = 4.5(x - 2)

Distribute

1.5x + 6 -3 = 4.5x - 9

Combine like terms

1.5x +3 = 4.5x -9

Subtract 1.5x from each side

1.5x -1.5x +3 = 4.5x -1.5x-9

3 = 3x-9

Add 9 to each side

3+9 = 3x-9+9

12 =3x

Divide each side by 3

12/3 = 3x/3

4=x

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it is correct

Step-by-step explanation:

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In the data set below, what is the mean absolute deviation?4461526If the answer is a decimal, round it to the nearest tenth.mean
bixtya [17]
I assume that the numbers are: 4,4,6,1,5,2,6
If so, then the MAD is 1.43

To find the MAD, you first find the mean of the list. It is 4.
Then find the absolute difference of each number from the mean.

Those values are: 0,0,2,3,1,2,2
Now find the mean of those numbers and you have about: 1.43
5 0
3 years ago
A wooden disk is shaped like a cylinder with a radius of 20.2 millimeters, and a height of 3.9 millimeters. What is the surface
asambeis [7]
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3 years ago
Solve for x<br> a 2.2<br> b 5.4<br> c 6.5<br> d 7.2
Reika [66]

Answer:

D

Step-by-step explanation:

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8 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
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