Question

P^3×q^2(p^4×q^n×r^3/r^-4)=p^7q^5r^7 What does n=

Answer 1

Answer:

$n = 3$

Step-by-step explanation:

Given:

The equation given is:

$p^3q^2(p^4q^n\times \frac{r^3}{r^{-4}})=p^7q^5r^7$

We simplify the given equation using the following law of indices:

$a^m\times a^n=a^{m+n}\\\frac{a^m}{a^n}=a^{m-n}$

Therefore,

$p^{3+4}q^{n+2}\times r^{3-(-4)})=p^7q^5r^7\\p^7q^{n+2}r^7=p^7q^5r^7\\q^{n+2}=q^5$

Since the base on both the sides is same, therefore, their exponents must also be same. This gives,

$n+2=5\\n=5-2\\n=3$

Therefore, the value of 'n' is 3.