the sum of three integers is 92. the second number is three times the first number. the third number is ten less than twice the
first number. find the integers
1 answer:
1st number = x
2nd number = 3x
3rd number = 2x-10
x +3x + 2x-10 =92
6x - 10 = 92
6x =102
x = 102/6
x = 17
1st number = 17
2nd number = 17*3 = 51
3rd number = 17 *2 = 34-10 = 24
17 + 51 + 24 = 92
3 numbers are 17, 51 and 24
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