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nasty-shy [4]
3 years ago
12

the sum of three integers is 92. the second number is three times the first number. the third number is ten less than twice the

first number. find the integers
Mathematics
1 answer:
Elanso [62]3 years ago
8 0

1st number = x

 2nd number = 3x

3rd number = 2x-10

x +3x + 2x-10 =92

6x - 10 = 92

6x =102

x = 102/6

x = 17

1st number = 17

2nd number = 17*3 = 51

 3rd number = 17 *2 = 34-10 = 24

17 + 51 + 24 = 92

 3 numbers are 17, 51 and 24

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