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Olegator [25]
3 years ago
15

The sum of the squares

Mathematics
1 answer:
Naddik [55]3 years ago
3 0
The two integers are 11 and 8, so the larger integer is 11.
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3 to the power of -4
leva [86]
Three to the power of negative four is 81
3 0
3 years ago
Find the length of the third side of the right triangle. Give an exact answer and an approximation to three decimal places if ne
trasher [3.6K]

Answer:

a = 32

Step-by-step explanation:

This is a right triangle and the square value of hypotenuse is equal to sum of square value of other two side lengths

68^2 = 60^2 + a^2

4624 = 3600 + a^2

4624 - 3600 = a^2

1024 = a^2 find the root for both sides

32 = a

8 0
3 years ago
-18,-13,-8,-3,....<br><br> Find the above sequential formula
zhuklara [117]

The first term (a) is - 18

You add 5 to get to the next term. Or you can solve it by taking any 2 consecutive terms and find their difference.

Formula

d = t4- t3

Givens

t4 = - 3

t3 = - 8

Solution 1

d = t4 - t3             Substitute

d = -3 -  ( - 8)        Remove the brackets

d = -3 + 8             Combine  

d = 5                    Difference

Remark

Find the general formula

tn = - a + (n - 1)d      Substitute

So term 20 =           Example    

t20 = -18 + (20 - 1)*5 Combine the inside of the brackets. Remove the brackets

t20 = - 18 + 19*5          Combine 19 and 5          

t20 = -18 + 95              "Subtract"

t20 = 77                        Answer

5 0
3 years ago
What is the value of x in the equation 1,331x3 − 216 = 0?
erma4kov [3.2K]
1331 x³ = 216
x³ = 216/1331
x = \sqrt[3]{ \frac{216}{1331} } =  \frac{6}{11}
Thank you.
4 0
3 years ago
3 - x/2 = 6 (Solve each equation) Check your answer
Yanka [14]
Answer to question
3-x/2=6
Subtract 3 from both sides
-x/2=3
Multiply 3 by -2
Final Answer: x=-6

Work check
3-x/2=6
Substitute -6 for x since you solved for x in the last equation
3-(-6)/2
Convert 3-(-6/2) to 3+6/2
3+6/2
Divide 6 by 2
3+3
Add
Final Answer: 6 (This 6 is the same 6 we used to solve for x in the first equation).
6 0
4 years ago
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