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swat32
3 years ago
14

Alex is ordering his girlfriend a bouquet of flowers for their anniversary.roses cost $5 each and carnations cost $2 each. He wo

uld like to include at least 3 flowers. To stay on budget he must not spend more than $36.
Mathematics
2 answers:
pshichka [43]3 years ago
5 0
The equations of the function is

Y=2x+ 5y
Y<(less than or equal to) 36
X+y>( greater than or equal to) 3

So to find one variable in the equation such as finding the amount of roses or carnations, you would have to do system of equations. Some ways of using system of equations is to use substitution, elimination, or graphing.
slamgirl [31]3 years ago
5 0

Step-by-step explanation:

Let x be number of roses and y be the number of carnations.

We have been given that  Alex would like to include at least 3 flowers. We can represent this information as:

x+y\geq 3...(1)

We are also told that roses cost $5 each and carnations cost $2 each and to stay on budget he must not spend more than $36.  We can represent this information as:

5x+2y\leq 36...(2)

Therefore, our system of inequalities that will represent the given situation is:

x+y\geq 3...(1)

5x+2y\leq 36...(2)      



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Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
4 years ago
PLZ HELP!<br>dont just answer something random for points:)tysm​
sergiy2304 [10]

Answer:

4(x^{2} -4)^{2} -76

Step-by-step explanation:

Take out 4:

4(x^2-8x)-12

=4(x^2-8x+16-16)-12

=4(x^2-8x+16)-64-12

=4(x^2-4)^2 - 76

=4(x^{2} -4)^{2} -76

6 0
3 years ago
Can someone help me pleaseeee? whoever answers first gets the brainliest
Amiraneli [1.4K]

Answer:

The answer is y= 5

3 0
3 years ago
Read 2 more answers
Anil weighed 95 kg. He went running every day and began to lose mass. After one month his mass was 74 kg. What was the percentag
Phoenix [80]
Percentage decrease formula =
difference / original x 100%

95-74=21
21/95 x 100% = 22.1052632 ≈ 22.1 ( 3sf )

hope my answer helps
7 0
4 years ago
Read 2 more answers
NEED ASAP!!!!
Sunny_sXe [5.5K]

Answer:

B

Step-by-step explanation:

Using the Triangle Inequality Theorem, two sides of the triangle should always add up to be greater than the third side or it is not a triangle.

5 + 2 = 7 This sum is less than the third side, 12. Therefore, this cannot make a triangle.

3 0
3 years ago
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