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madreJ [45]
3 years ago
6

NEED ASAP!!!!

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Using the Triangle Inequality Theorem, two sides of the triangle should always add up to be greater than the third side or it is not a triangle.

5 + 2 = 7 This sum is less than the third side, 12. Therefore, this cannot make a triangle.

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3(x-5) +4(x+1) ; x=2
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8 0
3 years ago
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Out of 400 applicants for a job, 184 are male and 78 are male and have a graduate degree. Step 1 of 2: What is the probability t
g100num [7]

Answer:

Step 1

P = 0.4239

Step 2

P = 0.624

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

There are 400 applicants for a job

184 are male

78 are male and have a graduate degree.

Step 1 of 2: What is the probability that a randomly chosen applicant has a graduate degree, given that they are male? Express your answer as a fraction or a decimal rounded to four decimal places.

Desired outcomes:

Number of male applicants with a graduate degree, which is 78

Total outcomes:

Number of male applicants, which is 184

Probability:

P = \frac{78}{184} = 0.4239

Step 2 of 2: If 125 of the applicants have graduate degrees, what is the probability that a randomly chosen applicant is male, given that the applicant has a graduate degree? Express your answer as a fraction or a decimal rounded to four decimal places.

Desired outcomes:

Number of male applicants with a graduate degree, which is 78

Total outcomes:

Number of applicants with graduate degrees, which is 115

Probability:

P = \frac{78}{125} = 0.624

3 0
3 years ago
find the equation of the pair of lines perpendicular to the lines pair represented by the equation ax^2-2hxy+by^2=0 and passing
Naddika [18.5K]

The equation of the pair of lines perpendicular to the lines given equation is b x^{2}-2 h x y+a y^{2}=0.

Solution:

Given equation is a x^{2}+2 h x y+b y^{2}=0.

Let m_1 and m_2 be the slopes of the given lines.

Sum of the roots = -\frac{\text {coefficient of } x y}{\text {coefficient of } y^{2}}

               $m_1+m_2=\frac{-2h}{b} – – – – – (1)

Product of the roots = -\frac{\text {coefficient of } x^2}{\text {coefficient of } y^{2}}

                    $m_1 \cdot m_2=\frac{a}{b} – – – – – (2)

The required lines are perpendicular to these lines.

Slopes of the required lines are $-\frac{1}{m_{1}} \text { and }-\frac{1}{m_{2}}

Required lines also passes through the origin,

therefore their y-intercepts are 0.

Hence their equations are:

$y=-\frac{1}{m_{1}}x \text { and }y=-\frac{1}{m_{2}}x

Do cross multiplication, we get

m_1y=-x \  \text{and} \  m_2y=-x

Add x on both sides of the equation, we get

x+m_1y=0 \  \text{and} \  x+m_2y=0

Therefore, the joint equation of the line is

\left(x+m_{1} y\right)\left(x+m_{2} y\right)=0

x^2+m_2xy+m_1xy+m_1m_2y^2=0

x^{2}+\left(m_{1}+m_{2}\right) x y+m_{1} m_{2} y^{2}=0

Substitute (1) and (2), we get

$x^{2}+\left(\frac{-2 h}{b}\right) x y+\left(\frac{a}{b}\right) y^{2}=0

To make the denominator same, multiply and divide first term by b.

$ \frac{b}{b} x^{2}+\left(\frac{-2 h}{b}\right) x y+\left(\frac{a}{b}\right) y^{2}=0

$\frac{bx^2-2hxy+ay^2}{b} = 0

Do cross multiplication, we get

b x^{2}-2 h x y+a y^{2}=0

Hence equation of the pair of lines perpendicular to the lines given equation is b x^{2}-2 h x y+a y^{2}=0.

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4 years ago
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Kaylis [27]

Answer:

option A is the answer hope you find it helpful

3 0
3 years ago
Find the exact value of tan 0
allsm [11]
Tan (0) is equal to 0
Sin (0) = 0
Cos (0) = 1

Tan = Sin/Cos
That means that Tan (0) = 0/1 or 0
3 0
3 years ago
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