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Vlada [557]
3 years ago
6

Helppppp please with this one hurry

Mathematics
2 answers:
attashe74 [19]3 years ago
5 0

2 : 6 = 1 : 3

4 : 12 = 1 : 3

6 : 18 = 1 : 3

8 : 24 = 1 : 3


Answer is 1 :3

mash [69]3 years ago
5 0

7:21 and 1:3 because r equals 3g

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y: (5, -5)

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If there are 624 calories in 3 servings, how many calories are in 1 serving
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208 calories

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You have to divide 624 by 3, and you get 208.

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Suppose that g(x) = f(x) + 5. Which statement best compares the graph of
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c

Step-by-step explanation:

this is because your adding 5 to f(x) which would be x not y (pretty sure) and g(x) is y. your not adding 5 to g(x) therefore not b. D and A would never be correct for this because that would be subtraction of 5

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Angela borrowed $1,500. She will Pay back this amount in 12 equal and payments. What is the amount of each payment Angela will m
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$120

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7 0
3 years ago
In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes
ale4655 [162]

Answer:

The sample mean is \bar{x}=14.371 min.

The sample standard deviation is \sigma = 18.889 min.

Step-by-step explanation:

We have the following data set:

\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

\bar{x} = \frac{{\sum}x}{n}

where, n is the number of values in the data set.

\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }

The mean of a sample is  \bar{x}=14.371.

Create the below table.

Find the sum of numbers in the last column to get.

\sum{\left(x_i - \overline{X}\right)^2} = 6422.0982

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 6422.0982 }{ 19 - 1} } \approx 18.889

7 0
3 years ago
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