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3 years ago

Helppppp please with this one hurry

Mathematics

2 answers:

attashe74 [19]3 years ago

5 0

2 : 6 = 1 : 3

4 : 12 = 1 : 3

6 : 18 = 1 : 3

8 : 24 = 1 : 3

Answer is 1 :3

mash [69]3 years ago

5 0

7:21 and 1:3 because r equals 3g

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Y varies directly as x. Y=42 when x=6. Find the value of y when x =15.

pentagon [3]

Answer:

y=120

Step-by-step explanation:

Y varies directly as x is written as

$y \alpha x$

introducing a constant

y=kx

from the question, when y=48, x=6

substitute it in the formula

48=6k

making k the subject by dividing through by 6

$\frac{48}{6} = \frac{6k}{6}$

k=48/6

k=8

put the value of k in the expression y=kx

y=8x

from the question,the value of y when x=15 is given by

y=8×15

y=120.

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3 years ago

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kolbaska11 [484]

Answer:

Step-by-step explanation:

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3 years ago

Identify the outliers of the data set. Then determine if the outlier increases or decreases the value of the mean.

Juli2301 [7.4K]

<h3>Answer: D) 76; increases</h3>

========================================================

Explanation:

The main group or cluster of values spans from 32 to 42 (inclusive).

Then off on its own is the value 76, which we consider an outlier. This value is fairly far from the group. As a rule, large outliers pull on the arithmetic mean to make it larger than it should be. Think of it like the outlier pulling on the mean as if it was done through a magnet or gravitational pull.

Similarly, small outliers pull the mean to the left to make it smaller than it should be. We don't have any small outliers in this case.

--------------

Let's consider the set

A = {32, 34, 35, 36, 37, 38, 38, 41, 42, 42, 46}

where I've sorted the values and I replaced 76 with 46.

Computing the mean of set A gets us

(32+34+35+36+37+38+38+41+42+42+46)/11 = 38.27 approximately

--------------

Now let's form this set

B = {32, 34, 35, 36, 37, 38, 38, 41, 42, 42, 76}

which is the original set your teacher gave you. It's nearly identical to set A, except that the 46 is now 76 again.

Compute the mean of set B

(32+34+35+36+37+38+38+41+42+42+76)/11 = 41

---------------

Set A has a mean of roughly 38.72 and set B has a mean of 41. We see that the mean has increased.

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sineoko [7]

Answer:

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