Answer with explanation:
Mean of this data set
Arranging the data set in ascending order
22, 22,25, 26, 28,30,31,37,37,41,45,48,49,51,51,63,64,64,65,69
Median =Middle observation ,if number of terms is odd
and if number of terms is even, divide number of terms by ,2 and then follow the procedure
To find the Outlier
Interquartile range = 57 - 29=28
Data values are approximately equally distributed on both sides of median.
That is, 43-22=21, and ,69 -43=26
So,we can say that there will be no outliers.
Graph will be positively skewed.
Mean > Median
So,mean will be better measure of central tendency because, 43.4-22=21.4, and 69-43.4=25.6
Option A: There are no outliers.
And, Option C: The Mean is good measure of central tendency.