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Inga [223]
3 years ago
12

Convert to the opposite units.​

Mathematics
1 answer:
aev [14]3 years ago
4 0

Answer:

\boxed{\text{3. }\dfrac{7\pi}{30} \text{; 4. } -20^{\circ}\text{; 5. } -\dfrac{720^{\circ}}{\pi}}

Step-by-step explanation:

Question 3

42^{\circ} \times \dfrac{\pi}{180^{\circ}} = \boxed{\dfrac{7\pi}{30}}

Question 4

-\dfrac{\pi}{9} \times \dfrac{180^{\circ}}{\pi}= \boxed{-20^{\circ}}

Question 5

-4\times \dfrac{180^{\circ}}{\pi}= \boxed{-\dfrac{720^{\circ}}{\pi}}

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= – 1 is a solution of the equation
Nina [5.8K]

Answer:

C

Step-by-step explanation:

substitute -1 into all of the formulas, if both sides are equal, then it is correct, for C:

2(x-2)+6 = 0, sub -1

2(-1-2)+6=0, simplify and work out

2(-3)+6=0

-6+6=0

0=0

4 0
3 years ago
If a,b,c are all non-zero numbers and a+b+c=0, prove that
Butoxors [25]

<em>Given - a+b+c = 0</em>

<em>To prove that- </em>

<em>a²/bc + b²/ac + c²/ab = 3</em>

<em>Now we know that</em>

<em>when x+y+z = 0,</em>

<em>then x³+y³+z³ = 3xyz</em>

<em>that means</em>

<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>

<em>Lets solve for LHS</em>

<em>LHS = a²/bc + b²/ac + c²/ab</em>

<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>

<em>by multiplying missing denominators,</em>

<em>now take common abc from denominator and you'll get,</em>

<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>

<em>Comparing one and two we can say that</em>

<em>(a³+b³+c³)/abc = 3</em>

<em>Hence proved,</em>

<em>a²/bc + b²/ac + c²/ab = 3</em>

6 0
2 years ago
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Answer:

Step-by-step explanation:

let the integers be x and y

x+y=-20

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x²+20x+99=0

x²+11x+9x+99=0

x(x+11)+9(x+11)=0

(x+11)(x+9)=0

x=-11,-9

when x=-11

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y=-20=11=-9

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y=-20+9=-11

so integers  are -11,-9

8 0
2 years ago
Read 2 more answers
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Answer:

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Answer:

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1)

res = (10.6+8.5+6.1)/2 = 12.6 kg

2)

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7 0
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